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3 years ago

What is the temperature of a gas that is expanded from 3.75 L at 37 degrees Celsius to 5.6 L?

Chemistry

1 answer:

deff fn [24]3 years ago

3 0

Answer:

190 °C

Step-by-step explanation:

The pressure is constant, so this looks like a case where we can use Charles’ Law:

V₁/T₁ = V₂/T₂ Invert both sides of the equation.

T₁/V₁ = T₂/V₂ Multiply each side by V₂

T₂ = T₁ × V₂/V₁

=====

V₁ = 3.75 L; T₁ = (37 + 273.15) K = 310.15 K

V₂ = 5.6 L; T₂ = ?

=====

T₂ = 310.15 × 5.6/3.75

T₂ = 310.15 × 1.49

T₂ = 463 K

t₂ = 463 – 273.15

t₂ = 190 °C

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Download pdf

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