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kirza4 [7]
3 years ago
8

Give two examples of energy transfer by conduction between two objects

Chemistry
1 answer:
algol133 years ago
7 0
A boat being accelerated by the engine

Bringing water to the boil in an electric kettle
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Which of the following is the best way to separate sugar from water?
kompoz [17]
I don't know the options but usually a small strainer or a coffee thing u put over a cup and let the water seep down and the sugar stays.
4 0
3 years ago
Read 2 more answers
A student has a piece of aluminum metal what is the most reasonable assumption a student can make about the metal
Gala2k [10]

Answer:

<h2>- It could be stretched into a thin wire.</h2>

Explanation:

As per the question, the most rational claim that the student can make about the aluminum metal is that 'it could be stretched into a thin wire' without breaking which shows its ductility. It is one of the most significant characteristics of a metal. Metals can conduct electricity in any state and not only when melted. Thus, option A is wrong. Options C and D are incorrect as metals neither have the same shape always nor do they break on hitting with a hammer. Therefore, <u>option E</u> is the correct answer.

3 0
3 years ago
A student is riding his bicycle the 4 km to school from his house. The graph
masya89 [10]

Answer:

Explanation:

ポイントをありがとう

4 0
3 years ago
Which are the product(s) of this chemical reaction? FeCl 3 + 3NH 4OH -&gt;
Vinvika [58]
The answer is D

FeCl3 + 3 NH4OH → Fe(OH)3 + 3 NH4Cl
5 0
2 years ago
Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment. Calcu
Svet_ta [14]

Answer:

V_1=23.3~mL

Explanation:

In this case, we have a dilution problem. We have to remember that in the dilution procedure we go from a solution with higher concentration to a solution with lesser concentration. Therefore we have to start with the dilution equation:

C_1*V_1=C_2*V_2

Now we can identify the variables:

C_1=~1.475_M

V_1=~?

C_2=~0.1374_M

V_2=~250.0~mL

If we plug all the values into the equation:

1.475_M*V_1=0.1374_M*250.0~mL

And we solve for V_1:

V_1=\frac{0.1374_M*250.0~mL}{1.475_M}

V_1=23.3~mL

I hope it helps!

8 0
3 years ago
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