Answer:
185.25 m/s
Explanation:
consider the motion of the combination of bullet and block after the collision
v₀ = initial speed just after the collision
v' = final speed = 0 m/s
μ = Coefficient of friction = 0.6
g = acceleration due to gravity = 9.8 m/s²
a = acceleration of the combination = - μ g = - (0.6) (9.8) = - 5.88 m/s²
d = stopping distance = 13 m
using the kinematics equation
v'² = v₀² + 2 a d
0² = v₀² + 2 (- 5.88) (13)
v₀ = 12.4 m/s
m = mass of the bullet = 9.9 g = 0.0099 kg
M = mass of the wood = 138 g = 0.138 kg
v = speed of bullet before collision
v₀ = speed of combination after the collision = 12.4 m/s
Using conservation of momentum
m v = (m + M) v₀
(0.0099) v = (0.0099 + 0.138) (12.4)
v = 185.25 m/s
Answer:
h= 46.66 m
Explanation:
Given that
Initial speed of the car ,u = 110 km/h
We know that
1 km/h= 0.277 m/s
u= 30.55 m/s
lets height gain by car is h.
The final speed of the car will be zero at height h.
v²=u²- 2 g h
v= 0 m/s
0²=30.55²- 2 x 10 x h ( g = 10 m/s²)
h= 46.66 m
Answer:
They two waves has the same amplitude and frequency but different wavelengths.
Explanation: comparing the wave equation above with the general wave equation
y(x,t) = Asin(2Πft + 2Πx/¶)
Let ¶ be the wavelength
A is the amplitude
f is the frequency
t is the time
They two waves has the same amplitude and frequency but different wavelengths.
Answer:
Explanation:
the object will not move as the force exerted is not sufficient enough to overcome its force of friction
