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Oksana_A [137]
3 years ago
6

A heavy boy and a lightweight girl are balanced on a mass-less seesaw. If they both move forward so that they are one-half their

original distance from the pivot point, what will happen to the seesaw? Assume that both people are small enough compared to the length of the seesaw to be thought of as point masses.A. It is impossible to say without knowing the masses.
B. It is impossible to say without knowing the distances.
C. The side the boy is sitting on will tilt downward.
D. Nothing will happen; the seesaw will still be balanced.
E. The side the girl is sitting on will tilt downward.
Physics
2 answers:
Rom4ik [11]3 years ago
4 0

Answer:

b) Nothing will happen,  the sea saw will still be balanced.

Explanation:

b) Nothing will happen,  the sea saw will still be balanced.

Reason:-

When two kids are balanced, the sum of torques on the seesaw will be zero.

if each kid, reduces their distances by half, then the torque of each kid will be half and the sum of torque of each on the seesaw will be zero.

Therefore the seesaw is balanced

Katyanochek1 [597]3 years ago
4 0

Answer:D. Nothing will happen; the seesaw will still be balanced

Explanation: According to the principles of moment which states that for a body to be at equilibrium, the sum of clockwise moments must be equal to the sum of anticlockwise moments.

if the mass-less seesaw was initially balanced at a particular distance, it will still be balanced if the boy and the girl move forward to cover half their initial distances from the pivot.

D perfectly depicts the outcome.

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In the early part of the 1900s, psychologists who broke down thought processes into their basic elements and analyzed them were
Svetlanka [38]

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8 0
3 years ago
How long will it take an object to move 100 meters if the object is traveling with and average speed of 0.5 meters per second
gogolik [260]
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4 0
3 years ago
Electricity is distributed from electrical substations to neighborhoods at 13000 V. This is a 60 Hz oscillating (AC) voltage. Ne
Levart [38]

Answer:

the number of turns in the primary coil is 13000

Explanation:

Given the data in the question;

V₁ = 13000 V

V₂ = 120 V

N₁ = ?

N₂ = 120 turns

the relation between the voltages and the number of turns in the primary and secondary coils can be expressed as;

V₁/V₂ = N₁/N₂

V₁N₂ = V₂N₁

N₁ = V₁N₂ / V₂

so we substitute

N₁ = (13000 V × 120 turns) / 120 V

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8 0
3 years ago
What is the electric field 4.0 m from the center of the terminal of a Van de Graaff with a 7.10 mC charge, noting that the field
Jobisdone [24]

Answer:

3984875 N/C

Explanation:

Applying,

E = kq/r².................. Equation 1

Where E = Electric field, q = charge, r = distance, k = coulomb's constant.

From the question,

Given: q = 7.10 mC = 0.0071 C, r = 4.0 m

Constant: k = 8.98×10⁹ Nm²/C²

Substitute these values into equation 1

E = 0.0071(8.98×10⁹)/4²

E = 3984875 N/C

Hence the electric field is 3984875 N/C

5 0
3 years ago
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