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lakkis [162]
3 years ago
11

Bob is pulling a 30kg filing cabinet with a force of 200N , but the filing cabinet refuses to move. The coefficient of static fr

iction between the filing cabinet and the floor is 0.80.
What is the magnitude of the friction force on the filing cabinet?
Physics
1 answer:
Lostsunrise [7]3 years ago
5 0

Answer:

Magnitude force of friction is 235.2 N

Explanation:

The force of friction is the product of weight and the coefficient of static friction

The force have to be bigger than 200N because it don't move

∑F= F_{n} - F_{fr}

F_{fr} = u*m*g\\F_{fr} = 0.80*30kg*9.8 \frac{m}{s^{2} } \\F_{fr} = 235.2 \frac{kg*m}{s^{2} } \\F_{fr} = 235.2 } N

The force on the filling cabinet

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A speeding motorist traveling with velocity Vm is spotted by a police car. The police car is initially at rest, but the instant
Svetlanka [38]

Answer:

Explanation:

Given

Let us suppose police car and motorist travel in straight line  and police car catches motorist after s distance

Distance travel by motorist

s=v_mt----1

Distance traveled by Police car

s=ut+\frac{at^2}{2}

s=0+\frac{a_pt^2}{2}

s=\frac{a_pt^2}{2}----2

from 1 & 2 we get

t=\frac{2v_m}{a_p}

(a)Velocity of Police car after t sec

v=u+a_pt

v=0+a_p\times \frac{2v_m}{a_p}

v=2v_m

(b)time taken by police car is

t=\frac{2v_m}{a_p}

(c)Distance travel by police car=\frac{2v_m^2}{a_p}

7 0
3 years ago
Ultrasound with a frequency of 4.257 MHz can be used to produce images of the human body. If the speed of sound in the body is t
shutvik [7]

Answer:

2.49 * 10^(-4) m

Explanation:

Parameters given:

Frequency, f = 4.257 MHz = 4.257 * 10^6 Hz

Speed of sound in the body, v = 1.06 km/ = 1060 m/s

The speed of a wave is given as the product of its wavelength and frequency:

v = λf

Where λ = wavelength

This implies that:

λ = v/f

λ = (1060) / (4.257 * 10^6)

λ = 2.49 * 10^(-4) m

The wavelength of the sound in the body is 2.49 * 10^(-4) m.

4 0
3 years ago
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