Answer: <u>30</u>
Step-by-step explanation:
Yvette- <em>100-7</em>
Isandro- <em>0+3</em>
1.) I'm going to speed up the process and multiply by 5.
Yvette: <em>100-7</em>
7 × 5 = 35
100-35= 65
65-35= 30
Isandro: <em>0+3 </em>
3 × 5 = 15
0+15= 15
15+15=<em> </em>30
2.) If they keep going on this pattern they will have the same number on the 10 round.
Hey number 8. Be super careful, less than always look at that it should be 5n-3
I would assume it would be dividing both sides by three although if someone were to actually solve this I would say multiply 2 and 3 together first.
Hope this helps :)
Is RS perpendicular to DF? Select Yes or No for each statement. R (6, −2), S (−1, 8), D (−1, 11), and F (11 ,4) R (1, 3), S (4,7
guajiro [1.7K]
I'll do the first one to get you started.
Find the slope of the line between R (6,-2) and S (-1,8) to get
m = (y2-y1)/(x2-x1)
m = (8-(-2))/(-1-6)
m = (8+2)/(-1-6)
m = 10/(-7)
m = -10/7
The slope of line RS is -10/7
Next, we find the slope of line DF
m = (y2 - y1)/(x2 - x1)
m = (4-11)/(11-(-1))
m = (4-11)/(11+1)
m = -7/12
From here, we multiply the two slope values
(slope of RS)*(slope of DF) = (-10/7)*(-7/12)
(slope of RS)*(slope of DF) = (-10*(-7))/(7*12)
(slope of RS)*(slope of DF) = 10/12
(slope of RS)*(slope of DF) = 5/6
Because the result is not -1, this means we do not have perpendicular lines here. Any pair of perpendicular lines always has their slopes multiply to -1. This is assuming neither line is vertical.
I'll let you do the two other ones. Let me know what you get so I can check your work.
