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Bumek [7]
3 years ago
10

Suppose that J and K are points on the number line. If JK=12 lies at 3 , where could K be located? If there are several location

s, separate them with commas.

Mathematics
1 answer:
zmey [24]3 years ago
8 0

Answer:

15, -9

Step-by-step explanation:

It is given that J and K are points on the number line. J lies at 3 and JK=12.

We kneed to find the location of K.

A number line is a straight line with numbers placed at equal intervals and extended infinitely in any direction.

If K lies on the left side of J then the location of K is

3 + 12 = 15

If K lies on the right side of J then the location of K is

3 - 12 = -9

The locations of K are defined by the below number.

Therefore the locations of K are 15 and -9.

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Land's Bend sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the intern
Naya [18.7K]

Answer:

80% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases (\mu_1-\mu_2) is [-9.132 , 23.332].

Step-by-step explanation:

We are given that a random sample of 7 sales receipts for mail-order sales results in a mean sale amount of $81.70 with a standard deviation of $18.75.

A random sample of 11 sales receipts for internet sales results in a mean sale amount of $74.60 with a standard deviation of $28.25.

Firstly, the Pivotal quantity for 80% confidence interval for the difference between population means is given by;

                            P.Q. =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }  ~ t__n__1-_n__2-2

where, \bar X_1 = sample mean sales receipts for mail-order sales = $81.70

\bar X_2 = sample mean sales receipts for internet sales = $74.60

s_1 = sample standard deviation for mail-order sales = $18.75

s_2 = sample standard deviation for internet sales = $28.25

n_1 = size of sales receipts for mail-order sales = 7

n_2 = size of sales receipts for internet sales = 11

Also, s_p=\sqrt{\frac{(n_1-1)s_1^{2} +(n_2-1)s_2^{2} }{n_1+n_2-2} } = \sqrt{\frac{(7-1)\times 18.75^{2} +(11-1)\times 28.25^{2} }{7+11-2} } = 25.11

<em>Here for constructing 80% confidence interval we have used Two-sample t test statistics as we don't know about population standard deviations.</em>

<em />

So, 80% confidence interval for the difference between population means, (\mu_1-\mu_2) is ;

P(-1.337 < t_1_6 < 1.337) = 0.80  {As the critical value of t at 16 degree

                                         of freedom are -1.337 & 1.337 with P = 10%}  

P(-1.337 < \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } } < 1.337) = 0.80

P( -1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } } < {(\bar X_1-\bar X_2)-(\mu_1-\mu_2)} < 1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } } ) = 0.80

P( (\bar X_1-\bar X_2)-1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } } < (\mu_1-\mu_2) < (\bar X_1-\bar X_2)+1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } } ) = 0.80

<u>80% confidence interval for</u> (\mu_1-\mu_2) =

[ (\bar X_1-\bar X_2)-1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } } , (\bar X_1-\bar X_2)+1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } } ]

= [ (81.70-74.60)-1.337 \times {25.11 \times \sqrt{\frac{1}{7} +\frac{1}{11} } } , (81.70-74.60)+1.337 \times {25.11 \times \sqrt{\frac{1}{7} +\frac{1}{11} } } ]

= [-9.132 , 23.332]

Therefore, 80% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases (\mu_1-\mu_2) is [-9.132 , 23.332].

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Divide 600,000 by 10,000.

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48.248 / 0.2 = Is this multiply or Divide? Please help me with the answer.
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The first side of a triangle is 9 m shorter than the second side. The third side is 3 times as long as the first side. The perim
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Answer:

Longest side is 18 m

Step-by-step explanation:

1st side : x -9

3rd : 3(x-9)

If perimeter is 39, then, x + (x-9) + 3(x-9) = 39

5x -36 = 39

5x = 75

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Therefore,

1st side = 6

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3 years ago
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Consider a circle whose equation is x2 + y2 – 2x – 8 = 0. Which statements are true? Select three options.
Kryger [21]

Answer:

The first, second, and fifth statements are correct.

Step-by-step explanation:

We are given a circle with the equation:

x^2+y^2-2x-8=0

And we want to select the statements that are true.

First, we can convert the equation into standard form. We can group each variable:

(x^2-2x)+(y^2)=8

And complete the square for the first term:

(x^2-2x+1)+(y^2)=8+1

Factor and simplify:

(x-1)^2+y^2=9

We can rewrite our equation as:

(x-(1))^2+(y-(0))^2=(3)^2

So, this tells us that we have a circle centered on (1, 0) with a radius of 3 units.

In this case, the first statement, second statement (the point (1,0) is on the x-axis), and fifth statements are correct (the square root of 9 is also 3).

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3 years ago
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