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Bumek [7]
3 years ago
10

Suppose that J and K are points on the number line. If JK=12 lies at 3 , where could K be located? If there are several location

s, separate them with commas.

Mathematics
1 answer:
zmey [24]3 years ago
8 0

Answer:

15, -9

Step-by-step explanation:

It is given that J and K are points on the number line. J lies at 3 and JK=12.

We kneed to find the location of K.

A number line is a straight line with numbers placed at equal intervals and extended infinitely in any direction.

If K lies on the left side of J then the location of K is

3 + 12 = 15

If K lies on the right side of J then the location of K is

3 - 12 = -9

The locations of K are defined by the below number.

Therefore the locations of K are 15 and -9.

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What is KN + IK?<br> !it’s not 1!
sergiy2304 [10]
The answer is 6, K-N is 4, and I-K is 2, and as we all know, 4+2=6
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3 years ago
C.J bought a bag of birdseed for 4.25 he paid with a 5.00 bill.How much change did he get back.
ruslelena [56]
The answer is .75 if you have 5.00 and You Spent 4.25 So 4 Quarters Is A Dollar if you take a quarter. away from that 4.00 you will end up with .75 cents from the 5.00
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Please help out !!!!
evablogger [386]

Answer:

x  = 8

Step-by-step explanation:

you have similar triangles here

so     2 is to 4  as  4 is to x

2/4 =  4/x

x = 8

8 0
3 years ago
The distance between 5,3 and 1,3
mel-nik [20]

Answer:

(4,0)

Step-by-step explanation:

(5,3) (1,3)

You need to subtract from the x axis on both coordinates and the y axis in both coordinates.

(5-1) (3-3)

(4,0)

I also checked on a graph as well, so it's correct.

4 0
3 years ago
Write the integral in one variable to find the volume of the solid obtained by rotating the first-quadrant region bounded by y =
Dovator [93]

Answer:

V = π ∫₀² (y² − 8y + 6√(2y)) dy

or

V = π ∫₀² (6x − 5x² + x³) dx

Step-by-step explanation:

y₁ = 0.5x²

y₂ = x

First, find the intersections of the curves.

0.5x² = x

x² = 2x

x² − 2x = 0

x (x − 2) = 0

x = 0 or x = 2

So the points of intersection are (0, 0) and (2, 2).

When we revolve this region about the line x = 3, we get a hollow shape that looks like an upside-down funnel, or a volcano.

One option is to use washer method to find the volume, by cutting a thin horizontal slice of thickness dy, inner radius 3−x₁ = 3−√(2y), and outer radius of 3−x₂ = 3−y.

V = ∫₀² π [(3−y)² − (3−√(2y))²] dy

V = ∫₀² π (9 − 6y + y² − 9 + 6√(2y) − 2y) dy

V = π ∫₀² (y² − 8y + 6√(2y)) dy

Another option is to use shell method to find the volume, by cutting a thin vertical slice of thickness dx, radius 3−x, and height y₂−y₁ = x−0.5x².

V = ∫₀² 2π (3 − x) (x − 0.5x²) dx

V = ∫₀² 2π (3x − 1.5x² − x² + 0.5x³) dx

V = ∫₀² 2π (3x − 2.5x² + 0.5x³) dx

V = π ∫₀² (6x − 5x² + x³) dx

The second option is arguably easier to evaluate, but either one will get you the same answer (V = 8π/3).

7 0
3 years ago
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