1) <u>Stereo-selective (or enantioselective)</u> reactions form predominately or exclusively one enantiomer.
2) Epoxidation is the addition of a single oxygen atom to an alkene to form an epoxide.
3) <u>Hydrogenation (or reduction)</u> of an alkene forms an alkane by addition of H₂.
4) <u>Dihydroxylation</u> is the addition of two hydroxy groups to a double forming, a 1,2-diol or glycol.
5) <u>oxidative</u> cleavage of an alkene breaks both the σ and π bonds of the double bond to form two carbonyl groups.
6) <u>Regioselective</u> reactions form predominately or exclusively one constitutional isomer.
7) <u>Syn</u> dihydroxylation results when an alkene is treated KMnO4 or OsO4, where each reagent adds two oxygen atoms to the same side of the double bond.
Answer:
Ya'll should really practice more because things like these are easy
Explanation:
Answer:
1.23 M
Explanation:
Molarity of a substance , is the number of moles present in a liter of solution .
M = n / V
M = molarity
V = volume of solution in liter ,
n = moles of solute ,
Moles is denoted by given mass divided by the molecular mass ,
Hence ,
n = w / m
n = moles ,
w = given mass ,
m = molecular mass .
From the question ,
w = given mass of NaCl = 7.2 g
As we know , the molecular mass of NaCl = 58.5 g/mol
Moles is calculated as -
n = w / m = 7.2 g / 58.5 g/mol = 0.123 mol
Molarity is calculated as -
V = 100ml = 0.1 L (since , 1 ml = 1/1000L )
M = n / V = 0.123 mol / 0.1 L = 1.23 M
Answer:
V₂ = 15.3
Explanation:
Given data:
Initial volume = 12.0 L
Initial temperature = 20°C
Final temperature =100°C
Final volume = ?
Solution:
First of all we will convert the temperature into kelvin.
20°C + 273 = 293 K
100°C + 273 = 373 K
Formula:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 12.0 L × 373 K / 293 k
V₂ = 4476 L.K /293 k
V₂ = 15.3
V₂ = 1566 L.K / 298 K
V₂ = 5.3 L
