Answer : The limiting reagent is 
Solution : Given,
Moles of methane = 2.8 moles
Moles of = 5 moles
Now we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
From the balanced reaction we conclude that
As, 2 mole of react with 1 mole of 
So, 5 moles of react with 
moles of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and is a limiting reagent and it limits the formation of product.
Hence, the limiting reagent is
The molar mass of M is 0.225g/mol and the element M is Hydrogen
If a metal M combines with an oxygen element to form the oxide, 
then the chemical reaction will be expressed as:
This shows that 4 moles of an unknown element M react with the oxygen element to produce the oxide
Given the following parameters
Mass of M = 0.890 grams
Mass of = 0.956 grams
Get the molar mass of M:
Molar mass = Mass/number of moles
Molar mass = 0.890/4
Molar mass = 0.225g/mol
Hence the molar mass of M is 0.225g/mol and the element M is Hydrogen
Learn more here: brainly.com/question/6996520
Beryllium<span> (Be), </span>magnesium<span> (</span>Mg), calcium (Ca), strontium (Sr<span>), </span>barium<span>(Ba) and radium (Ra). Elements are grouped together because they share similar properties.
Hope i help</span>
Answer:
There is no way of finding the volume of an irregular shape.
We cant find the volume of an irregular solid because we can never measure the volume of curves that are present in an irregularly shaped object. so we tend to place this irregular object in a beaker of water so that the volume of water displaced by it will actually show us the volume of object itself. And now we can conclude that water displacement is an effective way of measuring the volume of an irregular solid there is no way of finding the volume of an irregular shape.
Answer:
187.407g
Explanation:
Moles of solute = Molarity × Liters of solution
Multiply 0.60 M by 1.50L:
0.60 mol/ 1L×1.50L=0.9 mol
To obtain the mass of solute, we will need to the molar mass of BaCl2, which is 208.23g/mol:
Finally, multiply the number of moles by208.23g /mol
0.9mol×208.23g/1mol =187.407g
Boom, you have a mass of:
187.407g
