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Vladimir [108]
3 years ago
15

How many molecules of ammonia (NH3) are contained in 10 moles of NH3? Please provide the work if you could :)

Chemistry
2 answers:
AVprozaik [17]3 years ago
8 0

Answer : The number of molecules of ammonia contained are 6.022\times 10^{24}

Explanation : Given,

Moles of NH_3 = 10 moles

As we know that, 1 mole of substance contains 6.022\times 10^{23} number of molecules.

As, 1 mole of NH_3 contains 6.022\times 10^{23} number of NH_3 molecules

So, 10 mole of NH_3 contains 10\times 6.022\times 10^{23}=6.022\times 10^{24} number of NH_3 molecules

Therefore, the number of molecules of ammonia contained are 6.022\times 10^{24}

nlexa [21]3 years ago
3 0
<span>Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles. We do as follows:

 </span>10 mol NH3 ( 6.022 x 10^23 molecules / 1 mol ) = 6.022x10^24 molecules NH3
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How many grams of NH3 can be produced from 2.30 mol of N2 and excess H2.
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<h3>Answer:</h3>

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<h3>Explanation:</h3>

From the question we are given;

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we are required to calculate the mass of NH₃ that may be reproduced.

<h3>Step 1: Writing the balanced equation for the reaction </h3>

The Balanced equation for the reaction is;

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<h3>Step 2: Calculating the number of moles of NH₃</h3>

From the equation 1 mole of nitrogen gas reacts to produce 2 moles of NH₃

Therefore, the mole ratio of N₂ to NH₃ is 1 : 2

Thus, Moles of NH₃ = Moles of N₂ × 2

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<h3>Step 3: Calculating the mass of ammonia produced </h3>

Mass = Moles × molar mass

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Therefore;

Mass = 4.6 moles × 17.031 g/mol

         = 78.3426 g

         = 78.34 g

Thus, the mass of NH₃ produced is 78.34 g

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