Answer:
d
ionic bond is formed when there is transfer of electrons and is composed of a positive cation and a negative anion
Answer:
A
Explanation:
We are usually asked to close the valve of the gas cylinder in our various kitchens at home <u>due to the inflammable property of the Liquified Petroleum Gas.</u>
<em>Without closing the valve, the LPG would diffuse into our homes, and any form of spark would cause an explosion and lead to a fire. Lives and properties could be lost in the process.</em>
The correct option is A.
If the temperature is increased then reaction will shift to the left because heat is absorbed.
<h3>What is equilibrium state?</h3>
Equilibrium of any reaction is that state in which concentration of reactant and concentration of product will be constant.
Given chemical reaction is:
A(g) + 2B(g) ⇄ C(g) + D(g)
From the equilibrium state reaction will move only that side which will contribute to maintain the stable state. In the forward reaction heat is released as mention in the question. So, when the temperature of reaction is increased then it shifts towards the left side by absorbing the heat and maintain the stability.
Hence, option (2) is correct, i.e. It will shift to the left because heat is absorbed.
To know more about equilibrium, visit the below link:
brainly.com/question/14297698
First, we have to get:
1- The heat required to increase T of ice from -50 to 0 °C:
according to q formula:
q1 = m*C*ΔT
when m is the mass of ice = mol * molar mass
= 1 mol * 18 mol/g
= 18 g
and C is the specific heat capacity of ice = 2.09 J/g-K
and ΔT change in temperature = 0- (-50) = 50°C
by substitution:
∴q1 = 18 g * 2.09 J/g-K *50°C
= 1881 J = 1.881 KJ
2- the heat required to melt this mass of ice is :
q2 = n*ΔHfus
when n is the number of moles of ice = 1 mol
and ΔHfus = 6.01 KJ/mol
by substitution:
q2 = 1 mol * 6.01 KJ/mol
= 6.01 KJ
3- the heat required to increase the water temperature from 0°C to 60 °C is:
q3 = m*C*ΔT
when m is the mass of water = 18 g
C is the specific heat capacity of water = 4.18 J/g-K
ΔT is the change of Temperature of water = 60°C - 0°C = 60°C
by substitution:
∴q3 = 18 g * 4.18 J/g-K * 60°C
= 4514 J = 4.514 KJ
∴the total change of enthalpy = q1+q2+q3
= 1.881 KJ +6.01 KJ + 4.514 KJ
= 12.405 KJ