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ludmilkaskok [199]
3 years ago
6

A 3000 kg truck travelling at 50km/hr strikes a stationary 1000 kg car, locking the two vehicles

Physics
1 answer:
Papessa [141]3 years ago
6 0

Answer:

50 x 3000 = 150000/4000 = 37.5

37.5 I think.

Explanation:

Hope this helps!

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Which device transforms electrical energy to mechanical energy
Nonamiya [84]
Examples of devices that convert electrical energy into mechanical energy — in other words, devices that use electrical energy to move something — include:

the motor in today’s standard power drills
the motor in today’s standard power saws
the motor in an electric tooth brushes
the engine of an electric car
the motor in a fan
the motor in a remote control cars that runs on batteries. So your answer would be B. Motorsport
5 0
3 years ago
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Please need help on this
mote1985 [20]

-- Whether an object floats or sinks in water depends on whether its density is more or less than the density of water.

-- The density of the rock didn't change when she threw it into the lake.

-- The density of the water didn't change when she threw the rock into the lake.

-- The density of anything never depends on how much of it you have.

-- If the rock sank in two ounces of water, it'll sink in a billion gallons of water.

--  Choose ' <em>A </em>' .

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3 years ago
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Which description best models the energy transfer that occurs in the radiative zone?
Zinaida [17]

Answer : Option D) A dropped wallet is kicked around the floor of a busy train station.

Explanation : The description that best suits the model for the energy transfer that occurs in the radiative zone is -

<h3>A dropped wallet is kicked around the floor of a busy train station.</h3>

As in the radiation zone, which is also called as radiative zone or radiative region in the layer of a star's interior where energy is primarily transported toward the exterior by means of radiative diffusion and thermal conduction. This can be correlated with the example of a dropped wallet in a busy train station as the wallet would be kicked by many people who are in a hurry to travel, this represents the radiative diffusion. So, every time the wallet is being kicked by someone the energy is getting transformed.

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3 years ago
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An automobile starts from rest and accelerates to a final velocity in two stages along a straight road. Each stage occupies the
qaws [65]

Answer:

The answer is a2 = 4.48 m/s2

Explanation:

Let´s start with the equations we know:

  1. v_{f} = v_{o} +at
  2. t_{1} =t_{2} =t

Where:

  • v_{f} => Final velocity
  • v_{o} => Initial velocity
  • a => acceleration
  • t => time

Now, let´s divide the problem in Stage 1 and 2 and get equations for each stage:

Stage 1 knowns and unknowns:

  • v_{1o} =0\\v_{1f} = ?\\a_{1} =2.8[\frac{m}{s^{2} }] \\t_{1} =?

Stage 1 equation:

  • v_{1f} = v_{1o} + a_{1} t
  • v_{1f}= 0+2.8t\\v_{1f}=2.8t

Stage 2 knowns and unknowns:

  • v_{2o} =v_{1f} \\v_{2f}=2.6v_{1f} \\a_{2} =?\\t_{2}=?

Stage 2 equation:

  • v_{2f} = v_{2o} +a_{2}t
  • 2.6v_{1f} =v_{1f} +a_{2}t\\2.6v_{1f} -v_{1f} = a_{2}t\\1.6v_{1f} = a_{2}t

Now we can substitute the resultant equation from stage 1 into stage´s 2 equation:

  • 1.6(2.8t) = a_{2}t

We can see "t" is on both sides, so it cancels out and we are left with:

a_{2} = 4.48 [\frac{m}{s^{2} } ]

3 0
3 years ago
An archer practicing with an arrow bow shoots an arrow straight up two times. The first time the initial speed is vi and second
Amiraneli [1.4K]

Answer:

The maximum height reached in the second trial is 16times the maximum height reached in the first trial.

Explanation:

The following data were obtained from the question:

First trial

Initial speed (u) = v

Final speed (v) = 0

Second trial

Initial speed (u) = 4v

Final speed (v) = 0

Next, we shall obtain the expression for the maximum height reached in each case.

This is illustrated below:

First trial:

Initial speed (u) = v

Final speed (v) = 0

Acceleration due to gravity (g) = 9.8 m/s²

Height (h₁) =.?

v² = u² – 2gh₁ (going against gravity)

0 = (v)² – 2 × 9.8 × h₁

0 = v² – 19.6 × h₁

Rearrange

19.6 × h₁ = v²

Divide both side by 19.6

h₁ = v²/19.6

Second trial

Initial speed (u) = 4v

Final speed (v) = 0

Acceleration due to gravity (g) = 9.8 m/s²

Height (h₂) =.?

v² = u² – 2gh₂ (going against gravity)

0 = (4v)² – 2 × 9.8 × h₂

0 = 16v² – 19.6 × h₂

Rearrange

19.6 × h₂ =16v²

Divide both side by 19.6

h₂ = 16v²/19.6

Now, we shall determine the ratio of the maximum height reached in the second trial to that of the first trial.

This is illustrated below:

Second trial:

h₂ = 16v²/19.6

First trial:

h₁ = v²/19.6

Second trial : First trial

h₂ : h₁

h₂ / h₁ = 16v²/19.6 ÷ v²/19.6

h₂ / h₁ = 16v²/19.6 × 19.6/v²

h₂ / h₁ = 16

h₂ = 16 × h₁

From the above illustrations, we can see that the maximum height reached in the second trial is 16times the maximum height reached in the first trial.

8 0
3 years ago
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