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Lana71 [14]
3 years ago
8

Which description best models the energy transfer that occurs in the radiative zone?

Physics
2 answers:
Zinaida [17]3 years ago
5 0

Answer : Option D) A dropped wallet is kicked around the floor of a busy train station.

Explanation : The description that best suits the model for the energy transfer that occurs in the radiative zone is -

<h3>A dropped wallet is kicked around the floor of a busy train station.</h3>

As in the radiation zone, which is also called as radiative zone or radiative region in the layer of a star's interior where energy is primarily transported toward the exterior by means of radiative diffusion and thermal conduction. This can be correlated with the example of a dropped wallet in a busy train station as the wallet would be kicked by many people who are in a hurry to travel, this represents the radiative diffusion. So, every time the wallet is being kicked by someone the energy is getting transformed.

hodyreva [135]3 years ago
4 0

the answer is D) a dropped wallet is kicked around the floor of a busy train station

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Frequency and wavelength are inversely related. That is, when frequency increases, the value of the wavelength decreases and vice versa. The constant of proportionality of  the relation is the speed of light that has a value of 3.0x10^8 m/s. We calculate as follows:

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488x10^-9 = 3.8x10^8 / frequency
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4 years ago
A sky-diver jumps from a stationary balloon. His initial downwards acceleration is 10m/s².
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Explanation:

a. The force acting down is gravity, on Earth gravity is 10 m/s^2. When the skydiver jump, the acceleration will start out as -10 m/s^2, but it will eventually equals the air resistance , which is called terminal velocity.

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A new planet is discovered that has twice the Earth's mass and twice the Earth's radius. On the surface of this new planet a per
kirza4 [7]

Answer:

option B

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Weight of the person in the new planet = ?

We know acceleration due to gravity is calculated by using formula

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now, acceleration due to gravity on the new planet

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4 years ago
Calculate the electric field intensity at a point 3 cm away from point charge of 3 x 10^-9 C.
lukranit [14]

Answer:

The electric field intensity is <u>30000 N/C.</u>

Explanation:

Given:

Magnitude of the point charge is, q=3\times 10^{-9}\ C

Distance of the given point from the point charge is, d=3\ cm=0.03\ m

Electric field intensity is directly proportional to the magnitude of point charge and inversely proportional to the square of the distance of the point and the given charge.

Therefore, electric field intensity 'E' at a distance of 'd' from a point charge 'q' is given as:

E=\frac{kq}{d^2}

Plug in k=9\times 10^9\ N\cdot m^2/C^2, q=3\times 10^{-9}\ C, d=0.03\ m. Solve for 'E'.

E=\frac{(9\times 10^9\ N\cdot m^2/C^2)(3\times 10^{-9}\ C)}{(0.03\ m)^2}\\\\E=\frac{27}{0.0009}\ N/C\\\\E=30000\ N/C

Therefore, the electric field intensity at a point 3 cm from the point charge is 30000 N/C.

3 0
3 years ago
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