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myrzilka [38]
3 years ago
12

Which device transforms electrical energy to mechanical energy

Physics
2 answers:
Nonamiya [84]3 years ago
5 0
Examples of devices that convert electrical energy into mechanical energy — in other words, devices that use electrical energy to move something — include:

the motor in today’s standard power drills
the motor in today’s standard power saws
the motor in an electric tooth brushes
the engine of an electric car
the motor in a fan
the motor in a remote control cars that runs on batteries. So your answer would be B. Motorsport
geniusboy [140]3 years ago
4 0
The answer would be B. motor energy.
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A parallel-plate capacitor is charged by a 14.0 V battery, then the battery is removed. You may want to review (Pages 692 - 695)
Anika [276]

Answer:

Potential Difference = 14 V

Explanation:

We are told that when the capacitor plates are charged to a certain voltage, then we have;

ΔV = 14 volts

Now, the battery is disconnected, so here we have the potential difference between the plates to be given by the formula;

ΔV = Q/C

Now, the charge is conserved on the plates and the capacitance is constant, therefore in this case, the potential difference will remain the same.

Thus;

Potential Difference = 14 V

6 0
3 years ago
A dentist causes the bit of a high-speed drill to accelerate from an angular speed of 1.50 × 10 4 1.50×104 rad/s to an angular s
KATRIN_1 [288]

Answer:

0.32 s

Explanation:

Initial angular speed: \omega_i = 1.50 \cdot 10^4 rad/s

Final angular speed: \omega_f = 3.35\cdot 10^4 rad/s

Angular rotation: \theta=2.02\cdot 10^4 rad

The angular acceleration of the drill can be found by using the equation:

\omega_f^2 - \omega_i^2 = 2 \alpha \theta

Re-arranging it, we find \alpha, the angular acceleration:

\alpha = \frac{\omega_f^2 - \omega_i^2}{2\theta}=\frac{(3.35\cdot 10^4 rad/s)^2-(1.50\cdot 10^4 rad/s)^2}{2(2.02\cdot 10^4 rad)}=22,209 rad/s^2

Now we want to know the time t the drill takes to accelerate from

\omega_i =0

to

\omega_f = 6.90\cdot 10^4 rad/s

This can be found by using the equation

\omega_f = \omega_i + \alpha t

where \alpha is the angular acceleration we found previously. Solving for t,

t=\frac{\omega_f - \omega_i}{\alpha}=\frac{22,209 rad/s^2}{6.90\cdot 10^4 rad/s}=0.32 s

5 0
3 years ago
g the space in between two glass sheets has a volume of 0.025 m3. If the temperature of the gas is 290 K, what is the rms speed
Keith_Richards [23]

Complete Question

Argon gas (a monatomic gas) is sometimes used to insulate a double-pane window for purposes of insulation. In a particular window, the space in between two glass sheets has a volume of 0.025 \ m^3. If the temperature of the gas is 290 K. what is the rms speed of the gas atoms? The atomic mass of Argon is 39.9 u.(l u= 1.66x10-27 kg) Enter your answer in m/s

Answer:

The value is V_{rms} = 425.75 \  m/s

Explanation:

From the question we are told that

     The volume of the space in between the two glass sheet is  a =  0.025 \ m^3

     The temperature of the gas is T =  290 \  K

       The atomic mass of Argon is  m  = 39.9 \  u  =  39.9 * 1.66 *10^{-27} = 6.623 *10^{-26} \  kg

Generally the root mean square velocity is mathematically represented as

      V_{rms} =  \sqrt{\frac{3 K T}{ m } }

Here K is the Boltzmann constant  with value k  =  1.38 *10^{-23} \  m^3 \cdot kg \cdot s^{-2} \cdot K^{-1}

So

     V_{rms} =  \sqrt{\frac{3 *  1.38 *10^{-23} *  290 }{ 6.6234*10^{-26} } }

=>   V_{rms} = 425.75 \  m/s

3 0
3 years ago
Which of the following is the visible part of the spectrum of light?
mestny [16]
The visible spectrum<span> is portion of the </span>electromagnetic spectrum<span> that is </span>visible <span>to the </span><span>human eye.
</span>gamma rays, <span>sound waves, </span><span>microwaves are not the part of spectrum of light, whereas color is the portion of spectrum of light.</span>
6 0
3 years ago
Read 2 more answers
Help me please this is for physics
Yuri [45]
<h2>Hello there! :)</h2>

It's a pleasure to be helping you today with your<u> physics question!</u>

Answer:

23.1m/s

Explanation:

We want to find the initial speed of the ball.

To do this, we have to apply the formula for the time of flight of a projectile:

T=\frac{2_{v0~sin 0} }{g}

where θ = angle of flight

g = acceleration due to gravity

v0 = initial speed

Therefore, substituting the given values into the formula, we have that:

\boxed{4.2=\frac{2~x~_{v0~sin63} }{9.8}}

⇒ 2 ×_{v0} ×0.8910= 9.8 × 4.2

⇒\boxed{{v0}=\frac{9.8~times~4.2}{2~times~0.8910}}

\boxed{{v0} =23.1m/s}

That is the initial speed of the ball.

<em />

<em>I hope this helps you!</em>

<em>Good Luck with your Assignment!</em>

3 0
3 years ago
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