Calculate the work done when lifting a sack of potatoes with a force of 100N vertically 6m.

Define acceleration to show its scientific meaning

Damm [24]

Increase in speed or rate

8 0

3 years ago

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A ball is released from rest at a height of 10 m and falls freely to the

ElenaW [278]

Answer:

The new kinetic energy would be 16 times greater than before.

Explanation:

Kinetic energy is found using this formula:

KE = 1/2mv²
where KE = kinetic energy (J), m = mass (kg), and v = velocity (m/s)

We can see that kinetic energy is directly proportional to the square of the velocity, meaning that if the speed was increased by 4 times, then the kinetic energy would get increased by a factor of 16.

The velocity just before the ball hits the ground can be found by the equation:

√(2gh)

Let's substitute h = 10 m and h = 40 m into this formula.

√(2g(10))
√(2g(40))

We can see that the velocity increases by a factor of 4 (10 m → 40 m).

Therefore, this means that the kinetic energy would also be increased by a factor of (4)² = 16. Thus, the answer is D) The new kinetic energy would be 16 times greater than before.

6 0

3 years ago

Why do concave lenses always form virtual images?

MaRussiya [10]

A concave mirror and a converging lens will only produce a real image if the object is located beyond the focal point (i.e., more than one focal length away). The image of an object is found to be upright and reduced in size.

3 0

4 years ago

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What is your name³ tell me so i help yaya

noname [10]

Kenzi LOl why do you ask?

6 0

4 years ago

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A horizontal disk rotates about a vertical axis through its center. Point P is midway between the center and the rim of the disk

rjkz [21]

If the disk turns with constant angular velocity, the following statements about it are true

The linear acceleration of Q is twice as great as the linear acceleration of P
is moving twice Q as fast as P.

Answer: Options D and E

Explanation:

Let us consider that R is the radius of the circular disc. So as Q is on the rim, so the distance of Q from the centre of the disc is R and as P is the midpoint between centre and rim of the disk, so the distance of P from the centre is R/2.

As we know that the angular velocity of the circular disk will be equal to the ratio of distance covered by that point to the time taken. So the angular velocity at point Q will be

$\text { Angular velocity at point } Q=\frac{\text { Distance covered by point } Q}{\text { Time }}=\frac{2 \pi R}{T}=v$

As R is the distance of point Q from the centre of the disc.

Similarly ,

$\text { Angular velocity at point } P=\frac{\text { Distance covered by point } P}{\text { Time }}=\frac{2 \pi\left(\frac{\mathrm{R}}{2}\right)}{T}=\frac{\pi R}{T}=v^{\prime}$

So if we equate v with v’ we obtain that

$v=2 v^{\prime}$

Therefore, the point Q will be moving twice as fast as P. As the velocity of Q is more than O, the linear acceleration of point Q will also be twice as great as the linear acceleration of P.

This is because acceleration is directly proportional to the rate of change in velocity. So if velocity increases in the factor of 2, the acceleration of point Q will also increase twice with respect to point P.

5 0

4 years ago