A 48-kg woman pushes a 12-kg grocery cart with a force of 24 N. What is the magnitude of the force that the grocery cart exerts
1 answer:
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Answer:
the final temperature of the tea is 7.39⁰C.
Explanation:
Given;
mass of the tea, m = 375 g
specific heat capacity of the tea, C = 4.184 JJ/g°C
initial temperature of the tea, t₁ = 95°C
the final temperature of the tea, t₂ = ?
Energy lost by the refrigerator, Q = 137,460 J
The energy lost by the refrigerator is given by the following formula;
-Q = mc(t₂ - t₁)
-137,460 =375 x 4.184(t₂ - 95°C)
-137,460 = 1569(t₂ - 95°C)
Therefore, the final temperature of the tea is 7.39⁰C.
Answer:
∴ fractional compression = 1.34 × 10⁻²
Explanation:
given,
depth of Indian ocean = 3000 m
Bulk modulus of the water = 2.2 x 10⁹ N/m²
We know,
P = P₀ + ρgh
P₀ is the atmospheric pressure
P₀ = 10⁵ N/m²
ρ is the density of the water, 1000 Kg/m³
P = 10⁵ + 1000 × 9.8 × 3000 = 2.94 × 10⁷ N/m²
using formula,
B = P/{-∆V/V}
B is bulk modulus and { -∆V/V} is the fractional compression
∴ fractional compression = 1.34 × 10⁻²