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RoseWind [281]
2 years ago
13

PLEASE HELP ! 2 questions

Chemistry
2 answers:
lakkis [162]2 years ago
5 0

Answer:

3 and 2

Explanation:

solniwko [45]2 years ago
5 0

Answer:

3 and 2

Explaination

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If you start with 10ml of 0.75 m cu(no3)2 how much cu (s) in grams should be recovered in step #7
LenaWriter [7]
<span>0.48 grams. Not a well worded question since it's assuming I know the reactions. But I'll assume that since there's just 1 atom of copper per molecule of Cu(NO3)2, that the reaction will result in 1 atom of copper per molecule of Cu(NO3)2 used. With that in mind, we will have 0.010 l * 0.75 mol/l = 0.0075 moles of copper produced. To convert the amount in moles, multiply by the atomic weight of copper, which is 63.546 g/mol. So 0.0075 mol * 63.546 g/mol = 0.476595 g. Round the results to 2 significant figures, giving 0.48 grams.</span>
4 0
2 years ago
Which of the following examples best demonstrates kinetic energy?
Vlada [557]
Answer:-

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2 years ago
PLEASE HElP ASAP!!!!!!
stepan [7]

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7 0
2 years ago
A 250-mL aqueous solution contains 1.56 10–5 g of methanol and has a density of 1.03 g/mL. What is the concentration in ppm?
Hoochie [10]
First, calculate for the mass of the aqueous solution by multiplying the given volume (in mL) by the density (in g/mL). In mathematical equation, that is,

        m = ρV

where m is mass, ρ is density, and V is volume. Substituting the known values,

      m = (1.03 g/mL)(250 mL) = 257.5 g

To get the concentration in ppm, divide the given mass of methanol by the mass of the solution. Note that the parts-per million (ppm) is equal to mass of solute in milligram(mg) divided by the mass of solution in kilogram (kg)

      C (in ppm) = (1.56 x 10^-6 g)(1000 mg/1 g)   / (257.5 g)(1 kg/1000 g)

Simplifying,
     C (in ppm) = (1.56 x 10^-3 mg)/ 0.2575 kg

     C (in ppm) = 0.00606 ppm

<em>Answer: 0.00606 ppm</em>
     
7 0
2 years ago
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Why cant you use pure sodium for cooking
Alexus [3.1K]
Pure sodium can severely harm your body (toxic) which can lead to death
6 0
3 years ago
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