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vredina [299]
3 years ago
11

A student accidentally reversed the order of solvents A, B, and C in the column chromatography and used the acetone FIRST and th

en the remaining solvents. Predict what will happen to the student’s ability to separate compounds. Explain your reasoning
Chemistry
1 answer:
Neporo4naja [7]3 years ago
5 0

Answer:

It will be difficult

Explanation:

He should have started from a non-polar solvent, which will dissolve the non-polar compound and elute it first before using the polar solvent, acetone can dissolve both polar and non-polar compound, making a hitch in d separation

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HELP O DONT UNDERSTAND THIS!IM SOOO STRESSED HOW DO I SOLVE IT
katrin [286]

Answer:

.86

.48

Explanation:

19/25 x 4/4 = 86/100

86/100 = .86

12/25 x 4/4 = 48/100

48/100 = .48

4 0
2 years ago
An aqueous solution has a hydroxide-ion concentration of 1.0 x 10-3M. What is the pH of the solution?
alexandr402 [8]
11 with pemdas, you have to multiply all by 3
8 0
3 years ago
Which of these have the same number of particles as 1 mole of water H2O
Fed [463]

Answer:

It is equal to Avogadro's number (NA), namely 6.022 x1023. If we have one mole of water, then we know that it will have a mass of 2 grams (for 2 moles of H atoms) + 16 grams (for one mole O atom) = 18 grams.

Explanation:

The question is not very much clear.

If you are asking for molecules then 1 mole water= 6.023 * 10^23

If you are asking for atoms then 1 mole water= 6.023 * 10^23 * 3

If you are asking for particles then,

So, in your example you would have one mole of water molecules. If you dissociated those water molecules, than you would end up with 2 moles of hydrogen atoms, and one mole of oxygen atoms.

I hope that was helpful!

H=1 proton,1 electron

O=8 protons,8 neutrons and 8 electrons

total particles in one H2O molecule-28

total no. of particles in 1 mole of water- 6.023 * 10^23 * 28

8 0
2 years ago
In the equation CH4 + 2O2 --> 2H2O + CO2 What is the mass of CO2 produced when 35g of O2 reacts?
Anestetic [448]

Answer:

24.06 g of CO₂

Explanation:

The balanced equation for the reaction is given below:

CH₄ + 2O₂ —> 2H₂O + CO₂

Next, we shall determine the mass of O₂ that reacted and the mass of CO₂ produced from the balanced equation. This can be obtained as follow:

Molar mass of O₂ = 2 × 16 = 32 g/mol

Mass of O₂ from the balanced equation = 2 × 32 = 64 g

Molar mass of CO₂ = 12 + (2×16)

= 12 + 32

= 44 g/mol

Mass of CO₂ from the balanced equation = 1 × 44 = 44 g

SUMMARY:

From the balanced equation above,

64 g of O₂ reacted to produce 44 g of CO₂.

Finally, we shall determine the mass of CO₂ produced by the reaction of 35 g of O₂. This can be obtained as follow:

From the balanced equation above,

64 g of O₂ reacted to produce 44 g of CO₂.

Therefore, 35 g of O₂ will react to produce = (35 × 44)/64 = 24.06 g of CO₂.

Thus, 24.06 g of CO₂ were produced from the reaction.

8 0
2 years ago
Which of the following is the best choice for presenting the percent
Alik [6]
OD










hope this helps!!
3 0
3 years ago
Read 2 more answers
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