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kogti [31]
2 years ago
13

Shean has a piece of string 7/8 meter long. He uses 1/5 of he piece of string to tie a package and cuts the rest into 5 equal pa

rts. What is the length of the pieces.
Mathematics
1 answer:
Anastasy [175]2 years ago
5 0

Answer:

7/50 meter

Step-by-step explanation:

Total piece of string = 7/8 meter

Used string = 1/5 of the piece of string

Used string =

1/5 of 7/8 meter

= 1/5 × 7/8

= 7/40 meter

Balance = Total string - used string

= 7/8 - 7/40

= 35-7/40

= 28/40

Balance = 28/40 meter

cuts the rest into 5 equal parts. What is the length of the pieces.

28/40 ÷ 5

= 28/40 × 1/5

= 28 / 200

= 7/50 meter

Length of each piece = 7/50 meter

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Answer with explanation:

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(a)

Number of ways of Selecting 2 integers from 50 Integers ,so that their sum is even,

   =Selecting 2 Even integers from 50 Even Integers , and Selecting 2 Odd integers from 50 Odd integers ,as Order of arrangement is not Important, ,

        =_{2}^{50}\textrm{C}+_{2}^{50}\textrm{C}\\\\=\frac{50!}{(50-2)!(2!)}+\frac{50!}{(50-2)!(2!)}\\\\=\frac{50!}{48!\times 2!}+\frac{50!}{48!\times 2!}\\\\=\frac{50 \times 49}{2}+\frac{50 \times 49}{2}\\\\=1225+1225\\\\=2450

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(b)

Number of ways of Selecting 2 integers from 100 Integers ,so that their sum is Odd,

   =Selecting 1 even integer from 50 Integers, and 1 Odd integer from 50 Odd integers, as Order of arrangement is not Important,

        =_{1}^{50}\textrm{C}\times _{1}^{50}\textrm{C}\\\\=\frac{50!}{(50-1)!(1!)} \times \frac{50!}{(50-1)!(1!)}\\\\=\frac{50!}{49!\times 1!}\times \frac{50!}{49!\times 1!}\\\\=50\times 50\\\\=2500

=2500 ways

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