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3 years ago

Find the area of the composite figure below. 4,3,3,2,2

Mathematics

1 answer:

fredd [130]3 years ago

6 0

Answer:

The area of the figure is. 144.

you just have to multiply all the numbers.

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A coffee dispensary uses ⅘ of a barrel of coffee beans per batch of coffee they ship. Yesterday, the dispensary used 3 ⅕ of a ba

KengaRu [80]

Answer:

4 batches

Step-by-step explanation:

First, you need to convert the mix number into a single fraction:

3 1/5 = 16/5 total barrels of coffee beans used

This allows us to divide the numbers easier in the next step.

Next, because each batch uses 4/5 of a barrel of beans, you need to divide 16/5 by 4/5:

(16/5) / (4/5) = 16/4 = 4 batches

(The fives cancel out because they are the same divisor.)

I hope this helps!

-TheBusinessMan

4 0

4 years ago

Rewrite the parametric equations by eliminating the parameter:

Elodia [21]

I believe the answer is c. I hope that’s right! Good luck!

6 0

3 years ago

Read 2 more answers

What is the scale factor of the dilation?

inna [77]

Answer:

Step-by-step explanation:

the distance from the point of dilation to point C is 3

the distance from the point of dilation to point A is 9

9/3 = 3

hope this helps, pls mark brainliest :D

5 0

3 years ago

Rewrite 9cos 4x in terms of cos x.

rosijanka [135]

$\bf \qquad \textit{Quad identities}\\\\
sin(4\theta )=
\begin{cases}
8sin(\theta )cos^3(\theta )-4sin(\theta )cos(\theta )\\
4sin(\theta )cos(\theta )-8sin^3(\theta )cos(\theta )
\end{cases}
\\\\\\
cos(4\theta)=8cos^4(\theta )-8cos^2(\theta )+1\\\\
-------------------------------\\\\
9cos(4x)\implies 9[8cos^4(x)-8cos^2(x)+1]
\\\\\\
72cos^4(x)-72cos^2(x)+9$

---------------------------------------------------------------------------

as far as the previous one on the 2tan(3x)

$\bf tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\qquad tan({{ \alpha}} + {{ \beta}}) = \cfrac{tan({{ \alpha}})+ tan({{ \beta}})}{1- tan({{ \alpha}})tan({{ \beta}})}\\\\
-------------------------------\\\\$

$\bf 2tan(3x)\implies 2tan(2x+x)\implies 2\left[ \cfrac{tan(2x)+tan(x)}{1-tan(2x)tan(x)}\right]
\\\\\\
2\left[ \cfrac{\frac{2tan(x)}{1-tan^2(x)}+tan(x)}{1-\frac{2tan(x)}{1-tan^2(x)}tan(x)}\right]\implies 2\left[ \cfrac{\frac{2tan(x)+tan(x)-tan^3(x)}{1-tan^2(x)}}{\frac{1-tan(x)-2tan^3(x)}{1-tan^2(x)}} \right]
\\\\\\$

$\bf 2\left[ \cfrac{2tan(x)+tan(x)-tan^3(x)}{1-tan^2(x)}\cdot \cfrac{1-tan^2(x)}{1-tan(x)-2tan^3(x)} \right]
\\\\\\
2\left[ \cfrac{3tan(x)-tan^3(x)}{1-tan^2(x)-2tan^3(x)} \right]\implies \cfrac{6tan(x)-2tan^3(x)}{1-tan^2(x)-2tan^3(x)}$

4 0

3 years ago

2i(4+5i)(4-5I)/4+i find the quotient and express it in its simplest form

gulaghasi [49]

The answer is B, you should really learn how to calculate these yourself though because they come up a lot.

7 0

3 years ago

Read 2 more answers