9514 1404 393
Answer:
3a by 4a
Step-by-step explanation:
For dimensions L and W, the area and perimeter are ...
A = LW = 12a^2
P = 2(L+W) = 14a
Using the second equation, we can find L:
L +W = 7a . . . . . divide by 2
L = 7a -W
Substituting into the area formula gives the quadratic ...
(7a -W)(W) = 12a^2
W^2 -7aW +12a^2 = 0 . . . . arrange in standard form
(W -3a)(W -4a) = 0 . . . . . . . factor (find factors of 12 that total 7)
Then we have the two solutions ...
W = 3a, L = 4a
W = 4a, L = 3a
The rectangle dimensions are 3a by 4a.
Answer:
I didn't know and I tried ♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️♂️
<span>f(x) = 5(1/5)-x
f(x) = 5(5)x</span>
Answer:
(a)
The function f is continuous at [1,e] and differentiable at (1,e), therefore
the mean value theorem applies to the function.
(b)
= 1.71828
Step-by-step explanation:
(a)
The function f is continuous at [1,e] and differentiable at (1,e), therefore
the mean value theorem applies to the function.
(b)
You are looking for a point
such that

You have to solve for
and get that
= 1.71828
Answer:
26
Step-by-step explanation:
You have to divide the two numbers, which are 2 and 52