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3 years ago

10

If one parent has sickle cell anemia and the other parent is a carrier, what is the possibility that their child will have sickl

e cell anemia

1 answer:

earnstyle [38]3 years ago

5 0

It’s a 50 50 chance unless one parent has a dominate gene

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Determine the relative amounts (in terms of volume fractions) for a 15 wt% sn-85 wt% pb alloy at 100Â°c. the densities of tin an

nikdorinn [45]

Volume fraction = volume of the element / volume of the alloy

Volume = density * mass

Base: 100 grams of alloy

mass of tin = 15 grams

mass of lead = 85 grams

volume = mass / density

Volume of tin = 15g / 7.29 g/cm^3 = 2.06 cm^3

Volume of lead = 85 g / 11.27 g/cm^3 = 7.54 cm^3

Volume fraction of tin = 2.06 cm^3 / (2.06 cm^3 + 7.54 cm^3) = 0.215

Volume fraction of lead = 7.54 cm^3 / (2.06 cm^3 + 7.54 cm^3) = 0.785

As you can verify the sum of the two volume fractions equals 1: 0.215 + 0.785 = 1.000

6 0

3 years ago

An exciton is: A charged particle made of electrons A charged particle made of holes A neutral particle made of an electron and

Alex

Answer:

A neutral particle made of an electron and hole

Explanation:

Exciton

It is the combination of an electron and a hole ( hole refers to the vacancy of an electron ) . And , as both the electron and the hole have the same charge but the polarity is opposite , the combination will lead to a neutral compound , i.e. , Exciton have no charge and so neutral .

It is free to move in the nonmetallic crystal and since it charge less , it is difficult to detect it directly .

7 0

3 years ago

Consider n2 (g) + 3h2 (g) →→ 2nh3 (g). what is the mass of nitrogen gas required to react with 0.129 g h2?

Flura [38]

The given chemical reaction given above is already balanced such that the number of atoms in the left hand side of the equation is equal to that of the right hand side. Using the dimensional analysis, proper conversion factors and the molar masses,

mass of nitrogen = (0.129 g H₂)(1 mol H₂/2 g H₂)(1 mol N₂/3 mol H₂)(28 g N₂/1 mol N₂)
mass of nitrogen = 0.602 g N₂

Therefore, 0.602 g of nitrogen will be required for he reaction.

6 0

3 years ago

A mothball, composed of naphthalene (C10H8), has a mass of 1.52g. How many naphthalene molecules does it contain?

Anna35 [415]

The molar mass of naphthalene is calculated as follows,
10 x (12.01 g/ mol) + 8 x (1.01 g/mol) = 128.12 g/mol
Divide the given mass by the molar mass to determine the number of moles of naphthalene present in the ball.
n = 1.52 g / 128.12 g/mol = 0.01186 mole
Multiply the number of moles to number of moles per mole.
(0.01186 mol) x (6.022 x10^23 molecules / mole) = 7.14 x 10^21 molecules

8 0

3 years ago

Gaseous ammonia chemically reacts with oxygen O2 gas to produce nitrogen monoxide gas and water vapor. Calculate the moles of am

mel-nik [20]

Answer:

1.7 moles of ammonia, NH₃.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

4NH₃ + 5O₂ —> 4NO + 6H₂O

From the balanced equation above,

4 moles of NH₃ reacted to produce 4 moles of NO.

Finally, we shall determine the number of mole of ammonia, NH₃, needed to produce 1.7 moles of nitrogen monoxide, NO. This can be obtained as follow:

From the balanced equation above,

4 moles of NH₃ reacted to produce 4 moles of NO.

Therefore, 1.7 moles of NH₃ will also react to produce 1.7 moles of NO.

Thus, 1.7 moles of ammonia, NH₃, is required.

5 0

3 years ago