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Gnesinka [82]
3 years ago
6

How many molecules of copper sulfate are needed to produce 5.0×1024 molecules of sodium sulfate?

Chemistry
1 answer:
lubasha [3.4K]3 years ago
4 0

Answer:

5.0 × 10²⁴ molecules

Explanation:

Step 1: Write the balanced double displacement reaction

2 NaOH + CuSO₄ ⇒ Na₂SO₄ + Cu(OH)₂

Step 2: Calculate the moles corresponding to 5.0 × 10²⁴ molecules of Na₂SO₄

We will use Avogadro's number: there are 6.02 × 10²³ molecules in 1 mole of molecules.

5.0 × 10²⁴ molecule × 1 mol/6.02 × 10²³ molecule = 8.3 mol

Step 3: Calculate the moles of CuSO₄ required to produce 8.3 moles of Na₂SO₄

The molar ratio of CuSO₄ to Na₂SO₄ is 1:1. The moles of CuSO₄ required are 1/1 × 8.3 mol = 8.3 mol.

Step 4: Calculate the molecules corresponding to 8.3 moles of CuSO₄

We will use Avogadro's number.

8.3 mol × 6.02 × 10²³ molecule/1 mol = 5.0 × 10²⁴ molecule

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Answer:

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Explanation:

The given reaction can be written in the form of chemical equation as shown below as:

X+2Y\rightarrow 2XY_2

According to law of conservation of mass, the moles of each substance in the reaction must be equal on both reactant and product side.

Also, the question asks for the gas which is diatomic. XY_2 cannot be diatomic as the formula contains 3 atoms.

Between gas X and gas Y , <u>X has to be diatomic for the reaction to balance </u>as:

X_2+2Y\rightarrow 2XY_2

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What are the four symbols for physical states of reactants and products?
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3) tritium (₁³H), with mass number 3 (two neutrons, n° = 3 -1, n° = 2).

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To what family of the periodic table does this new element probably belong
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6 0
3 years ago
18. How many moles of atoms are there in each of
Lelechka [254]

a) 1 mole of Ne

b) i/2 mole of Mg

c) 1570 moles of Pb.

d) 2.18125*10^-13 moles of oxygen.

                     

Explanation:

The number of moles calculated by Avogadro's number in 6.23*10^23 of Neon.

6.23*10^23= 1/ 6.23*10^23

                   = 1 mole

The number of moles calculated by Avogadro's number in 3.01*10^23 of  Mg

3.2*10^23=1/6.23*10^23

                = 1/2 moles of Pb.

Number of moles in 3.25*10^5 gm of lead.

atomic weight of Pb=

n=weight/atomic weight

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Number of moles 4.50 x 10-12 g O

number of moles= 4.50*10^-12/16

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3 0
3 years ago
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