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DaniilM [7]
3 years ago
7

Calculate the molarity of a solution that contains 0.175 mol of zncl2 n exactly 150 ml of solution.

Chemistry
2 answers:
notka56 [123]3 years ago
4 0

Explanation:

Molarity is the number of moles present in liter of a solution.

Mathematically,    Molarity = \frac{\text{no. of moles}}{\text{volume in liter}}

It is given that no. of moles present into the solution are 0.175 mol and volume is 150 ml.

As 1 ml = 0.001 L. So, 150 ml will be equal to 0.15 L.

Hence, calculate the molarity as follows.

    Molarity = \frac{\text{no. of moles}}{\text{volume in liter}}

                  = \frac{0.175 mol}{0.15 L}                

                  = 1.16 M

Thus, we can conclude that molarity of the given solution is 1.16 M.

scoray [572]3 years ago
3 0
Molarity = mol/L

0.175 mol
0.15 L (1000 mL = 1 L)

Molarity = 0.175 mol/0.15 L = 1.1666667 M
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Write the two balanced equations, one for the incomplete combustion of methane (to form carbon monoxide and water vapor), and an
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2CH_{4(g)} +3O_{2(g)} -->2CO(g)+4H_{2}O_{(g)}\\CH_{4(g)} +2O_{2(g)} -->CO_{2(g)} +2H_{2}O_{(g)} \\

Explanation:

2CH_{4(g)} +3O_{2(g)} -->2CO(g)+4H_{2}O_{(g)}\\CH_{4(g)} +2O_{2(g)} -->CO_{2(g)} +2H_{2}O_{(g)} \\

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3 years ago
identify the reagents you would use to convert each of the following compounds into pentanoic acid: (a) 1-pentene (b) 1-bromobut
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a)BH3.THF is used to convert 1-pentane to pentanoic acid and b)NaCN is used to convert Bromobutane to pentanoic acid.

a) The conversion of 1-pentane to pentanoic acid using BH3, also known as hydroboration-oxidation, is a two-step reaction involving the reaction of 1-pentane with borane (BH3), followed by oxidation of the resulting 1-pentylborane with hydrogen peroxide or other oxidizing agents.

In the first step, 1-pentane reacts with borane (BH3) to form 1-pentylborane, through a process known as hydroboration. This reaction is catalyzed by a Lewis acid, such as aluminum chloride, and proceeds via a hydride transfer from the borane to the 1-pentane.

In the second step, the 1-pentylborane is oxidized to pentanoic acid using hydrogen peroxide (H₂O₂) or other suitable oxidizing agents. The oxidation is catalyzed by an acid, such as hydrochloric acid (HCl), and proceeds via a proton transfer from the 1-pentylborane to the hydrogen peroxide. The end result is the conversion of 1-pentane to pentanoic acid.

The overall chemical reaction for the conversion of 1-pentane to pentanoic acid using borane (BH₃) and hydrogen peroxide (H₂O₂) is as follows:

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The overall reaction can be represented as follows:

1-Bromo butane + NaCN → Pentanoic Acid + NaBr

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brainly.com/question/26283409

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