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2 years ago

How much time will it take for a truck to travel 20 meters if it is traveling at 4 m/s?

Physics

2 answers:

poizon [28]2 years ago

7 0

The answer to this question is 5s

ss7ja [257]2 years ago

4 0

Answer:

<h2>The answer is 5 s</h2>

Explanation:

The time taken can be found by using the formula

$t = \frac{d}{v} \\$

d is the distance

v is the velocity

From the question we have

$t = \frac{20}{4} \\$

We have the final answer as

Hope this helps you

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2 years ago

20 kg object travels 28 meter and stops. coefficient friction= 0.085 how much work was done by friction?

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3 years ago

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3 years ago

Read 2 more answers

At t=0 bullet A is fired vertically with an initial (muzzle) velocity of 450 m/s. When 3s. bullet B is fired upward with a muzzl

Debora [2.8K]

Answer:

At time 10.28 s after A is fired bullet B passes A.

Passing of B occurs at 4108.31 height.

Explanation:

Let h be the height at which this occurs and t be the time after second bullet fires.

Distance traveled by first bullet can be calculated using equation of motion

$s=ut+0.5at^2 \\$

Here s = h,u = 450m/s a = -g and t = t+3

Substituting

$h=450(t+3)-0.5\times 9.81\times (t+3)^2=450t+1350-4.9t^2-29.4t-44.1\\\\h=420.6t-4.9t^2+1305.9$

Distance traveled by second bullet

Here s = h,u = 600m/s a = -g and t = t

Substituting

$h=600t-0.5\times 9.81\times t^2=600t-4.9t^2\\\\h=600t-4.9t^2 \\$

Solving both equations

$600t-4.9t^2=420.6t-4.9t^2+1305.9\\\\179.4t=1305.9\\\\t=7.28s \\$

So at time 10.28 s after A is fired bullet B passes A.

Height at t = 7.28 s

$h=600\times 7.28-4.9\times 7.28^2\\\\h=4108.31m \\$

Passing of B occurs at 4108.31 height.

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3 years ago

Find the focal length of a lens of power-2.0D . What type of lens is this ?

olga_2 [115]

Answer: f = - 0.50 m, negative (diverging) lens

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Means f = ( 1/ -2.0 ) m = -0.50 m

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2 years ago