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dangina [55]
3 years ago
6

A 2-kg book falls off a shelf. It hits a student traveling 2 m/s. How much kinetic energy does the book have?

Physics
1 answer:
Gekata [30.6K]3 years ago
3 0

4 J

1/2 mv^2 is ke formula

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Why was Thompson's Plum pudding model a significant departure from previous models?
PSYCHO15rus [73]

Answer:

Thomson's cathode-ray tube experiments led him to develop the plum-pudding model, which stated that each atom had positively charged particles spread throughout its negatively charged matter. Reword the statement so it is true. ... More alpha particles were deflected than he expected.

Explanation:

Well.. I hope it helps you..

Just correct me if I'm wrong..

5 0
3 years ago
you stand on a straight desert road at night and observe a vehicle approaching. this vehicle is equipped with two small headligh
inysia [295]

Answer:

The distance that you marginally able to discern that there are two headlights rather than a single light source is 6.084 km

Explanation:

Given:

d = distance = 0.679 m

λ = wavelength of the light = 537 nm = 537x10⁻⁹m

dp = pupil diameter = 4.81 mm = 0.00481 m

Question: What distance, in kilometers, are you marginally able to discern that there are two headlights rather than a single light source, dx = ?

For the separation of the peak from the central maximum it is:

sin\theta =\frac{\lambda }{d_{p} } =\frac{537x10^{-9} }{0.00481} =1.116x10^{-4}

In this case, the two small sources of the headlights have the same angle as the images that form inside the eye

d_{x} =\frac{d}{sin\theta } =\frac{0.679}{1.116x10^{-4} } =6.084x10^{3} m=6.084km

7 0
4 years ago
Where do buoyant forces act on?
Mademuasel [1]

Answer:

The upward buoyancy force on an object acts through the overall center of buoyancy, being the centroid of the displaced volume of fluid. The weight force on the object acts through its center of gravity.

5 0
3 years ago
Before 1960, people believed that the maximum attainable coefficient of static friction for an automobile tire on a roadway was
Eduardwww [97]

Answer:

4.18

Explanation:

Givens  

The car's initial velocity  v_{i}= 0 and covering a distance Δx = 1/4 mi = 402.336 m in a time interval t = 4.43 s.  

Knowns

We know that the maximum static friction force is given by:

f_{s_max} =μ_s*n                         (1)

Where μ_s is the coefficient of static friction and n is the normal force.  

Calculations  

(a) First, we calculate the acceleration needed to achieve this goal by substituting the given values into a proper kinematic equation as follows:

Δx=v_{i} +\frac{1}{2} at^2

a=41 m/s

This is the acceleration provided by the engine. Applying Newton's second law on the car, so in equilibrium, when the car is about to move, we find that:  

f_{y}=n-mg=0\\ n=mg\\f_{x}=F-f_{s,max} =0\\ f_{s,max}=F=ma\\

Substituting (3) into (1), we get:

f_{s,max}= μ_s*m*g

Equating this equation with (4), we get:

ma=  μ_s*m*g

 μ_s=a/g

      =4.18

3 0
4 years ago
If a basball is project upwards from the ground level with an initial velovaity of 32 feet per second, then it's height is a fun
inessss [21]

Answer:

Maximum height reached by the ball is 32 meters.

Explanation:

It is given that,

If a baseball is project upwards from the ground level with an initial velocity of 32 feet per second, then it's height is a function of time. The equation is given as :

s=-8t^2+32t...........(1)

t is the time taken

s is the height attained as a function of time.

Maximum height achieved can be calculated as :

\dfrac{ds}{dt}=0

\dfrac{d(-8t^2+32t)}{dt}=0

-16 t + 32 = 0

t = 2 seconds

Put the value of t in equation (1) as :

s=-8(2)^2+32(2)

s = 32 meters

So, the maximum height reached by the ball is 32 meters. Hence, this is the required solution.

6 0
4 years ago
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