Answer:
Maximum speed ( v ) = 10.4 m/s (Approx)
Explanation:
Given:
Amplitude A = 15.0 cm = 0.15 m
Frequency f = 11.0 cycles/s (Hz)
Find:
Maximum speed ( v )
Computation:
Angular frequency = 2πf
Angular frequency = 2π(11)
Angular frequency = 69.14
Maximum speed ( v ) = WA
Maximum speed ( v ) = 69.14 x 0.15
Maximum speed ( v ) = 10.371
Maximum speed ( v ) = 10.4 m/s (Approx)
Answer:
2.1 m/s
Explanation:
Momentum is conserved, so:
m₁ u₁ + m₂ u₂ = (m₁ + m₂) v
(9.1 kg) (6.6 m/s) = (9.1 kg + 19.3 kg) v
v = 2.1 m/s
25 m/s² is the object's acceleration
m1a1=m2a2
m1=5kg
m2=3 kg
a1= 15 m/s²
a2=?
m1a1=m2a2
a2=m1a1/m2
a2=5×15÷3
a2= 25 m/s²
Acceleration is a vector variable that describes the rate at which an object changes its velocity.
An object is said to be accelerating if its velocity is changing. Occasionally, a moving object can change its velocity by the same amount each second. a moving object whose speed fluctuates by 10 m/s every second. This is referred to as a constant acceleration since the velocity is changing by a fixed amount each second.
The difference between an object with a constant acceleration and one with a constant velocity must be understood. Do not be fooled! If an object's velocity changes, whether it does so by a constant amount or a variable amount, then it is accelerating. Furthermore, something that is travelling at a steady speed is not accelerating.
To know more about acceleration visit : brainly.com/question/3046924
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