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Sauron [17]
1 year ago
12

When a constant force acts upon an object, the acceleration of the object varies inversely with its mass. When a certain constan

t force acts upon an
object with mass 5 kg, the acceleration of the object is 15 m/s². If the same force acts upon another object whose mass is 3 kg
what is this object's
acceleration?
Physics
1 answer:
soldi70 [24.7K]1 year ago
8 0

25  m/s² is the object's acceleration

m1a1=m2a2

m1=5kg

m2=3 kg

a1= 15 m/s²

a2=?

m1a1=m2a2

a2=m1a1/m2

a2=5×15÷3

a2= 25  m/s²

Acceleration is a vector variable that describes the rate at which an object changes its velocity.

An object is said to be accelerating if its velocity is changing. Occasionally, a moving object can change its velocity by the same amount each second. a moving object whose speed fluctuates by 10 m/s every second. This is referred to as a constant acceleration since the velocity is changing by a fixed amount each second.

The difference between an object with a constant acceleration and one with a constant velocity must be understood. Do not be fooled! If an object's velocity changes, whether it does so by a constant amount or a variable amount, then it is accelerating. Furthermore, something that is travelling at a steady speed is not accelerating.

To know more about  acceleration visit : brainly.com/question/3046924

#SPJ9

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6 0
3 years ago
The person has an upward acceleration of 0.70 m/s^2 and is lifted from rest through a distance of 13 m. A rescue helicopter lift
Alex

Answer:

a)

840 N

b)

10920 J

c)

- 10192 J

d)

4.3 m/s

Explanation:

a)

T = tension force in the cable in upward direction = ?

a = acceleration of the person in upward direction = 0.70 m/s²

m = mass of the person being lifted = 80 kg

Force equation for the motion of person in upward direction is given as

T - mg = ma

T = m (g + a)

T = (80) (9.8 + 0.70)

T = 840 N

b)

d = distance traveled in upward direction = 13 m

W_{t} = Work done by tension force

Work done by tension force is given as

W_{t} = T d

W_{t} = (840) (13)

W_{t} = 10920 J

c)

d = distance traveled in upward direction = 13 m

W_{g} = Work done by person's weight

Work done by person's weight is given as

W_{g} = - mg d

W_{g} = - (80 x 9.8) (13)

W_{g} = - 10192 J

d)

F_{net} = Net force on the person = ma = 80 x 0.70 = 56 N

v₀ = initial speed of the person = 0 m/s

v = final speed

Using work-energy theorem

F_{net} d = (0.5) m (v² - v₀²)

(56) (13) = (0.5) (80) (v² - 0²)

v = 4.3 m/s

6 0
4 years ago
1. When you shine light with a wavelength of 400 nm at 50% intensity, what is observed?
riadik2000 [5.3K]

Answer:

I think it might be A

Explanation:

the reason I think this answer is because the intensity is 50%.

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3 years ago
a string with fixed ends is made to go into standing wave patterns. at a given tension, the lowest frequency for which a certain
lakkis [162]

Answer:

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Explanation:

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3 years ago
Calculate the wavelength associated with electrons moving with p.d of 1500v
Artist 52 [7]

Answer:

3.16X10∧-11 m

Explanation:

1/2 mv2 = qV (KE = Electric potential energy)

velocity = √2qV/m = √( 2X 1.6X10∧-19 X 1500/9.11X10∧-31)

2.3X10∧7m/s

now use De Broglie equation

λ = h/mv

= 6.62X10∧-34/( 9.11X10∧-31 X 2.3X10∧7)

3.16 X 10∧-11 m

or

use the above equations and substitute to get the final eqiation

λ = h/√(2mqV) = 3.16X 10∧-11 m

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3 years ago
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