Ice floats on the surface of water 'cause <span>ice is less dense than water.
In short, Your Answer would be Option A
Hope this helps!</span>
Answer:
It is balanced
Explanation:
There is 1 Carbon, 2 Hydrogen, and 1 Oxygen on the right and 1 Carbon, 1 Oxygen and 2 Hydrogen on the left. This equation is balanced.
It was a compound, hence it needed to be separated into its individual components by chemical means.
Answer:
The specific heat of alloy ![C_{alloy} = 1.007 \frac{KJ}{Kg K}](https://tex.z-dn.net/?f=C_%7Balloy%7D%20%3D%201.007%20%5Cfrac%7BKJ%7D%7BKg%20K%7D)
Explanation:
Mass of the alloy = 30.5 gm = 0.0305 kg
Initial temperature = 93 °c = 366 K
Mass of water = 50 gm = 0.05 kg
Initial temperature = 22 °c = 295 K
Final temperature of the mixture = 31.1 °c = 304.1 K
From the energy conservation principal the heat lost by the alloy is equal to heat gain by the water.
Heat lost by alloy
![Q_{alloy} = m C (T_{f}- T_{i} )](https://tex.z-dn.net/?f=Q_%7Balloy%7D%20%3D%20m%20C%20%28T_%7Bf%7D-%20T_%7Bi%7D%20%20%29)
------- (1)
Heat gain by water
![Q_{w} = (0.05) (4.18) (304.1 - 295)](https://tex.z-dn.net/?f=Q_%7Bw%7D%20%3D%20%280.05%29%20%284.18%29%20%28304.1%20-%20295%29)
------- (2)
Equation (1) = Equation (2)
![(1.88795) C_{alloy} = 1.9019](https://tex.z-dn.net/?f=%281.88795%29%20C_%7Balloy%7D%20%3D%201.9019)
![C_{alloy} = 1.007 \frac{KJ}{Kg K}](https://tex.z-dn.net/?f=C_%7Balloy%7D%20%3D%201.007%20%5Cfrac%7BKJ%7D%7BKg%20K%7D)
This is the specific heat of alloy.
Answer:
Explanation:
Amount HCl = 0.455mole
Molar mass = 1 + 35.5 = 36.5g/mol
Amount = mass/molar mass
:- mass = Amount × Molar mass
Mass = 16.97g