Answer:
26 grams of D will be produced.
Explanation:
The reaction is given by:
A + B -----> C + D
Mass of A reacted = 21 g
Mass of B reacted = 22 g
Mass of C formed = 17 g
Mass of D formed = m =?
According to law of conservation of mass, the total mass of the reactants used is equal to the total mass of the product formed.
Then:
mass of A reacted + mass of B reacted = mass of C formed + mass of D formed
21 + 22 = 17 + m
m = 26 g
Answer:
The highest sea-level pressure on Earth occurs in Siberia
Explanation:
where the Siberian High often attains a sea-level pressure above 1050 mbar (105 kPa; 31 inHg), with record highs close to 1085 mbar (108.5 kPa; 32.0 inHg).
Answer: Option (D) is the correct answer.
Explanation:
Valence shell is the shell present on the outermost core of an atom and electrons present in the valence shell are known as valence electrons.
If an atom has completely filled valence shell then it means the atom is not reactive in nature because it is already stable.
But when an atom has less than eight electrons in its valence shell then it means to attain stability the atom will readily attract electrons towards itself.
As the given element 1 has 8 electrons in its valence shell. Hence, it is not reactive in nature but element 2 has 6 valence electrons. So, in order to attain stability element 2 will readily attract 2 electrons from a donor atom.
Thus, we can conclude that element 2 is more reactive because it does not have a full valence shell, so it will attract electrons.
Answer:
4.504g of acetic acid
Explanation:
The acetic acid in reaction with NaOH produce acetate ion, thus:
CH₃COOH + NaOH → CH₃COO⁻ + H₂O + Na⁺
<em>That means the moles of acetate buffer comes, in the first, from the acetic acid</em>
As you need 500mL (0,500L) of a 0.150M acetate buffer, moles are:
0.500L × (0.150mol / 1L) = <em>0.075 moles of acetate</em>. That is:
0.075mol = [CH₃COO⁻] + [CH₃COOH]
Thus, grams of acetic acid you need to prepare the buffer are:
0.075 moles acetic acid × (60.05g / 1mol) = <em>4.504g of acetic acid</em>