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aleksandrvk [35]
3 years ago
12

Sodium azide is stable at room temperature but decomposes quickly at temperatures above 300°C. It is moderately inexpensive to m

anufacture but is highly toxic. Read this article on the effects of undeployed airbags. Based on the article, does sodium azide seem like a good match for the criteria and constraints you listed in part A? In what ways is sodium azide a good choice for an airbag design, and in what ways is it not?
https://app.edmentum.com/content-delivery//resource/90760c74-ecf7-42a4-aeee-3ef8fae15eab
Chemistry
1 answer:
Katen [24]3 years ago
4 0

The heat generated causes sodium azide to decompose into sodium metal and nitrogen gas, which inflates the car's air bags. Under normal circumstances, this molecule is quite stable. If heated, though, it will fall apart.Eating as little as 50 milligrams (less than two-thousandths of an ounce) of sodium azide can lead to collapse and a coma-like state within five minutes as blood pressure plummets and heart rate skyrockets. Ingest a few grams, and death occurs within 40 minutes.To prevent microbial contamination, sodium azide can be added to an antibody preparation to a final concentration of 0.02% (w/v). Many Abcam antibodies already contain this preservative at concentrations ranging from 0.02 to 0.05%. This will be indicated on the datasheets in the section titled “Storage buffer”Sodium azide is highly toxic. Ingestion of 100 to 200 mg can result in headache, respiratory distress, and diarrhea. Target organs are the central nervous system and the brain.Heavy metal azides, such as lead azide are primary high explosives detonable when heated or shaken. Heavy-metal azides are formed when solutions of sodium azide or HN3 vapors come into contact with heavy metals or their salts.

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A gas has a volume of 3.25 liters at 54 C and 231 kPa of pressure. At what temperature will the same gas take up 4.35 liters of
Firdavs [7]

Answer: 318 K

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 231 kPa

P_2 = final pressure of gas = 168 kPa

V_1 = initial volume of gas = 3.25 L

V_2 = final volume of gas = 4.35 L

T_1 = initial temperature of gas = 54^oC=273+54=327K

T_2 = final temperature of gas = ?

Now put all the given values in the above equation, we get:

\frac{231\times 3.25}{327}=\frac{168\times 4.35}{T_2}

T_2=318K

At 318 K of temperature will the same gas take up 4.35 liters of space and have a pressure of 168 kPa

4 0
4 years ago
Air at 293 K and 750 mm Hg pressure has a relative humidity of 80%. What is its percent humidity? The vapour pressure of water a
Mekhanik [1.2K]

Answer : The correct option is, (c) 79.62

Explanation :

The formula used for percent humidity is:

\text{Percent humidity}=\text{Relative humidity}\times \frac{p-p^o_v}{p-p_v}\times 100   ..........(1)

The formula used for relative humidity is:

\text{Relative humidity}=\frac{p_v}{p^o_v}       ...........(2)

where,

p_v = partial pressure of water vapor

p^o_v = vapor pressure of water

p = total pressure

First we have to calculate the partial pressure of water vapor by using equation 2.

Given:

p=750mmHg

p^o_v=17.5mmHg

Relative humidity = 80 % = 0.80

Now put all the given values in equation 2, we get:

0.80=\frac{p_v}{17.5mmHg}

p_v=14mmHg

Now we have to calculate the percent humidity by using equation 1.

\text{Percent humidity}=0.80\times \frac{750-17.5}{750-14}\times 100

\text{Percent humidity}=79.62\%

Therefore, the percent humidity is 79.62 %

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How many grams calcium sulfite are in a 3.87 mole sample?
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Answer:did you get the answer

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