Answer:
percent elongation is 54%
reduction area is 73%
Explanation:
original diameter = 0.500 in
gauge length = 2.000 in
diameter of the specimen is 0.260 in
fractured gauge length = 3.08 in
solution
we get here ductility in terms of percent elongation that is express as
elongation = ........1
elongation =
elongation = 0.54
so percent elongation is 54%
and
now we get cross section of this section is
Ao = × 0.5²
Ao = 0.1963 in²
so now calculate final cross section area
A(f) = × 0.26²
A(f) = 0.0530 in²
so percent reduction in area will be
percent reduction area = ..............2
percent reduction area =
percent reduction area = 73%
there is reduction area is 73%
Answer:
the third statement is true
Explanation:
given data
Lenovos cost more than Dells
Lenovos cost less than Apples
solution
we have given 1st statement that is express as
cost (Lenovo) > cost (Dell) ..................1
and
2nd statement that is express as
cost (Lenovo) < cost (Apple)
so we can say it as
cost (Apple) > cost (Lenovo) ......................2
and
now above Both equation 1 and 2 can be written as
cost (Apple) > cost (Lenovo) > cost (Dell) .........................3
so we can say cost of Apples is more than the cost of Lenovos and the cost of Dells
so as that given 3rd statement is true
Answer: The outer surface temperature is .
Explanation:
Given: Heat = 3 kW (1 kW = 1000 W) = 3000 W
Area = 10
Length = 2.5 cm (1 cm = 0.01 m) = 0.025 m
Thermal conductivity = 0.2 W/m K
Temperature (inner) =
Formula used is as follows.
where,
K = thermal conductivity
A = area
L = length
= inner surface temperature
= outer surface temperature
Substitute the values into above formula as follows.
Thus, we can conclude that the outer surface temperature is .
Answer:
A). Check the results obtained with a leaner setting of the mixture.
Explanation:
Answer:
A
Explanation:
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