Answer:
72.78 °C
Explanation:
Q=mcΔT
Q is energy added in joules (262)
m is mass in grams (15)
c is specific heat capacity in J/g°C (0.24)
ΔT is change in temperature in °C and thus the thing we need
262=15x0.24xΔT
262=3.6xΔT
72.777777777777777 = ΔT
Answer:
![\boxed{\text{57.7 g} }](https://tex.z-dn.net/?f=%5Cboxed%7B%5Ctext%7B57.7%20g%7D%20%7D)
Explanation:
The first step is to calculate the molar mass of H₂O:
![\begin{array}{rcr}\text{2 H} & = & 2.02\\\text{1 O} & = & 16.00\\\text{TOTAL} & = & \mathbf{18.02}\\\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcr%7D%5Ctext%7B2%20H%7D%20%26%20%3D%20%26%202.02%5C%5C%5Ctext%7B1%20O%7D%20%26%20%3D%20%26%2016.00%5C%5C%5Ctext%7BTOTAL%7D%20%26%20%3D%20%26%20%5Cmathbf%7B18.02%7D%5C%5C%5Cend%7Barray%7D)
So, 1 mol has a mass of 18.02 g.
Next you calculate the mass of 3.2 mol of H₂O
![\begin{array}{rcl}m & = & \text{3.2 mol H$_{2}$O} \times \dfrac{\text{18.02 g H$_{2}$O}}{\text{1 mol H$_{2}$O}}\\ & = &\boxed{\textbf{57.7 g H$_{2}$O}} \\\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcl%7Dm%20%26%20%3D%20%26%20%5Ctext%7B3.2%20mol%20H%24_%7B2%7D%24O%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B18.02%20g%20H%24_%7B2%7D%24O%7D%7D%7B%5Ctext%7B1%20mol%20H%24_%7B2%7D%24O%7D%7D%5C%5C%20%26%20%3D%20%26%5Cboxed%7B%5Ctextbf%7B57.7%20g%20H%24_%7B2%7D%24O%7D%7D%20%5C%5C%5Cend%7Barray%7D)
Scientist can come to different conclusions based off the same data.
Answer:
i really dont know i just need points bad sorry bud