1) 0.89% m/v = 0.89 grams of NaCl / 100 ml of solution
=> 8.9 grams of NaCl in 1000 ml of solution = 8.9 grams of NaCl in 1 liter of solution
2) Molarity = M = number of moles of solute / liters of solution
=> calculate the number of moles of 8.9 grams of NaCl
3) molar mass of NaCl = 23.0 g /mol + 35.5 g/mol = 58.5 g / mol
4) number of moles of NaCl = mass / molar mass = 8.9 g / 58.5 g / mol = 0.152 mol
5) M = 0.152 mol NaCl / 1 liter solution = 0.152 M
Answer: 0.152 M
Answer:
-209 kJ
Explanation:
I did the math. You're welcome ;)
Avagadros law states that volume of gas is directly proportional to number of moles of gas at constant pressure and temperature.

where V -volume , n - number of moles
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
substituting these values in the equation

V = 44.8 L
answer is C. 44.8 L
Answer:
Thus, first conversion of mass of methane into moles by dividing it with 16.04 g/mol
Mass = 138.63 g
Explanation:
The balanced chemical reaction is shown below:-

Firstly the moles of methane gas reacted must be calculate as:-
Given, mass of methane = 50.6 g
Molar mass of methane gas = 16.04 g/mol
The formula for the calculation of moles is:-

Thus, from the reaction stoichiometry,
1 mole of methane produces 1 mole of carbon dioxide
Also,
3.15 mole of methane produces 3.15 mole of carbon dioxide
Moles of
= 3.15 mole
Molar mass of
= 44.01 g/mol
Mass = Moles*Molar mass =
g = 138.63 g