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Darina [25.2K]
3 years ago
13

Write equations for the half-reactions that occur at the anode and cathode for the electrolysis of each of the following aqueous

solutions. NaBr, PbI2, Na2SO4
Chemistry
1 answer:
nirvana33 [79]3 years ago
7 0
For NaBr(aq) hydrogen gas is formed at the cathode. Hydrogen in water is reduced to hydrogen gas. For NaBr(aq), bromine, Br2(l), will be produced instead of oxygen gas at the anode. 

<span>For sodium sulfate hydrogen gas is formed at the cathode. Hydrogen in water is reduced to hydrogen gas. Oxygen gas will be produced at the anode. </span>

<span>Should someone suggest that sodium metal is formed at the cathode, rest assured that that can't happen. Sodium metal reacts with water to make Na+. </span>

<span>Lead(II) iodide is insoluble in water. Therefore, not much will happen since there is no electrolyte.</span>
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Marine life is least affected by the temperature fluctuations of the atmosphere.

Explanation:

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A car traveling at a constant speed travels 175 miles in four hours. How many minutes will it take for the car to travel 1000 fe
elena-14-01-66 [18.8K]

It takes 0.26 minutes to travel 1000 feet

<u>Solution:</u>

Given that car traveling at a constant speed travels 175 miles in four hours

Distance = 175 miles

Time taken = 4 hours

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1 mile = 5280 feet

175 miles = 5280 x 175 feet = 918720 feet

Also we know that,

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4 hours = 60 x 4 minutes = 240 minutes

Thus, we got,

Distance = 918720 feet

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<em><u>Speed is given by formula:</u></em>

speed = \frac{distance}{time}

speed = \frac{918720}{240} = 3828

Thus speed of car is 3828 feet per minute

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Let "x" be the minutes needed for 1000 feet

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Thus it takes 0.26 minutes to travel 1000 feet

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