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3 years ago

Which statement describes steps involved in the production of hydroelectric power?

Physics

2 answers:

Tju [1.3M]3 years ago

8 0

Answer:

D. Falling water turns a turbine that helps generate electricity.

Explanation:

Here is the proof:

viktelen [127]3 years ago

4 0

Answer:

Answer is D.......Falling water turns a turbine that helps generate electricity.

Explanation:

Hydropower plants capture the energy of falling water to generate electricity. A turbine converts the kinetic energy of falling water into mechanical energy. Then a generator converts the mechanical energy from the turbine into electrical energy.

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What are the orders of the lunar cycle?

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The 8 moon phases in order are New moon, Waxing Crescent, First Quarter, Waxing Gibbous, Full moon, Waning Gibbous, Third Quarter, and finally Waxing Crescent.

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3 years ago

When a cup is placed on a table, which force prevents the cup from falling to the ground? A. gravitational force B. normal force

stealth61 [152]

its B... normal force

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3 years ago

Read 2 more answers

Another droplet of the same mass falls 8.4 cm from rest in 0.250 s, again moving through a vacuum. Find the charge carried by th

Andrej [43]

Answer:

The charge carried by the droplet is $1.330\times10^{-19}\ C$

Explanation:

Given that,

Distance =8.4 cm

Time = 0.250 s

Suppose tiny droplets of oil acquire a small negative charge while dropping through a vacuum in an experiment. An electric field of magnitude $5.92\times10^4\ N/C$ points straight down and if the mass of the droplet is $2.93\times10^{-15} kg$

We need to calculate the acceleration

Using equation of motion

$s=ut+\dfrac{1}{2}at^2$

Put the value into the formula

$8.4\times10^{-2}=0+\dfrac{1}{2}\times a\times(0.250)^2$

$a=\dfrac{8.4\times10^{-2}\times2}{(0.250)^2}$

$a=2.688\ m/s^2$

We need to calculate the charge carried by the droplet

Using formula of electric filed

$E=\dfrac{F}{q}$

$q=\dfrac{ma}{E}$

Put the value into the formula

$q=\dfrac{2.93\times10^{-15}\times2.688}{5.92\times10^4}$

$q=1.330\times10^{-19}\ C$

Hence, The charge carried by the droplet is $1.330\times10^{-19}\ C$

8 0

3 years ago

I have been trying to do number 2 and I just don’t know what the answer is if you can help me thank you so mush

skelet666 [1.2K]

Answer:

Strong Positive Linear Line Correlation

Explanation:

According to the diagram, there is a strong positive linear line correlation between velocity and distance of galaxies. Hubble showed that galaxies are receding away from people with a velocity that is proportional to their distance from people more distant galaxies recede faster than nearby galaxies.

About the diagram: Velocity is the distance relation among extra-galactic nebulae. Radial velocities is corrected for solar motion, are plotted against distances estimated from involved stars and mean luminosities of nebulae in a cluster. The black discs and full line represent the solution for solar motion by using the nebulae individually; the circles and broken line represent the solution combining the nebulae into groups; the cross represents the mean velocity corresponding to the mean distance of 22 nebulae whose distances could not be estimated individually.

4 0

2 years ago

M= 1000 g g= 10 m/s2 h= 10 K.E at GROUND = 400 j M.E = ....... ........J the answer is 400 so plz explain how

Simora [160]

Answer:

M = 500 J

Explanation:

Given that,

Mass, M = 1000 g = 1 kg

Height, h = 10 m

Potential energy is given by :

P = mgh

P = 1×10×10

P = 100 J

The kinetic energy at ground = 400 J

Mechanical energy = sum of kinetic and potential energy

So,

M = 100 + 400

M = 500 J

So, the mechanical energy of the system is 500 J.

4 0

3 years ago