Answer:
The charge on the third object is − 21.7nC
Explanation:
From Gauss's Law
Φ = Q/ε₀
where;
Φ is the total electric flux through the shell = − 533 N⋅m²/C
Q is the total charge Q in the shell = ?
ε₀ is the permittivity of free space = 8.85 x 10⁻¹²
From this equation; Φ = Q/ε₀
Q = Φ * ε₀ = − 533 * 8.85 x 10⁻¹²
Q = −4.7 X 10⁻⁹ C = -4.7nC
Q = q₁ + q₂ + q₃
− 4.7nC = − 14.0 nC + 31.0 nC + q₃
− 4.7nC − 17nC = q₃
− 21.7nC = q₃
Therefore, the charge on the third object is − 21.7nC
The answer is B. magnesium I am pretty sure
Answer:
<h2>0.67 m/s²</h2>
Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
![a = \frac{f}{m} \\](https://tex.z-dn.net/?f=a%20%3D%20%20%5Cfrac%7Bf%7D%7Bm%7D%20%20%5C%5C%20)
f is the force
m is the mass
From the question we have
![a = \frac{38}{57} = \frac{2}{3} \\ = 0.666666...](https://tex.z-dn.net/?f=a%20%3D%20%20%5Cfrac%7B38%7D%7B57%7D%20%3D%20%20%5Cfrac%7B2%7D%7B3%7D%20%20%20%5C%5C%20%20%3D%200.666666...)
We have the final answer as
<h3>0.67 m/s²</h3>
Hope this helps you
Are there options? because there is 2 things im thinking of