Answer:
a) 19440 km/h²
b) 10 sec
Explanation:
v₀ = initial velocity of the car = 45 km/h
v = final velocity achieved by the car = 99 km/h
d = distance traveled by the car while accelerating = 0.2 km
a = acceleration of the car
Using the kinematics equation
v² = v₀² + 2 a d
99² = 45² + 2 a (0.2)
a = 19440 km/h²
b)
t = time required to reach the final velocity
Using the kinematics equation
v = v₀ + a t
99 = 45 + (19440) t
t = 0.00278 h
t = 0.00278 x 3600 sec
t = 10 sec
Strong alien you got there good luck bud you never asked a question
Answer:
≅3666.67 N
Explanation:
Use Newton's 2nd law, F = ma where F=force applied, m = mass of the object,
a = acceleration acquired by the object.
a= (v-u)/t where v = final velocity, u = initial velocity and t = time taken
calculate a = (30-0)/9 ≅ 3.33 m/s2
Then F = 1100×a = 3666.67 N
