Help please!! asap!!

Find the area of the largest square contained by a circle of radius r = 1cm. Explain your answer and justify that it is correct.

Elena-2011 [213]

Answer:

2 square cm

Step-by-step explanation:

Given :

A square is inscribed in a circle whose radius is r = 1 cm

Therefore, the diameter of the circle is 2 r = 2 x 1

= 2 cm.

So the diagonal of the square is 2r.

Using the Pythagoras theorem, we find each of the side of the triangle is $r \sqrt 2$ .

Therefore, the area of the square is given by $\text{(side)}^2$

= $(r\sqrt 2)^2$

$= 2 r^2$

$= 2 (1)^2$

$=2 \ cm^2$

Hence the area of the largest square that is contained by a circle of radius 1 cm is 2 cm square.

7 0

3 years ago

What is the area of a parallelogram whose bases are 9

Nady [450]

 Base=9cm

height=3 cm

Area of parallelogram=b*h

 =9*3

 =27cm^2.

Hope this will help u...:)

6 0

3 years ago

69 = 50 + s; 17, 18, 19

serious [3.7K]

The answer is 19 pls mark brainliest if correct

6 0

3 years ago

Read 2 more answers

What is 0.123 rounded to the nearest tenth

Vikentia [17]

$0.123\\\\digit\ in\ the\ tenths\ place\ is\ \boxed1$

If the number you are rounding is followed by 5, 6, 7, 8, or 9, round the number up (+1).

If the number you are rounding is followed by 0, 1, 2, 3, or 4, round the number down (no change).

$0.\underline{1}23\approx\boxed{0.1}$

3 0

3 years ago

Read 2 more answers

HURRY PLEASE!!! I NEED TO TURN THIS IN SOON i need an explanation too.

Dominik [7]

Answer:

X = 30°, y = 15° and z = 150°.

Reason: Look below.

Step-by-step explanation:

Hey there!

When we look into the figure, we find that;

For x:

x+ 2x + 90° = 180° {Being linear pair}

or, 3x = 180°-90°

or, 3x = 90°

or, x= 90°/3

Therefore, X = 30°.

For y :

2y = x = 30° {Alternate angles are equal}

or, 2y = 30°

y = 30°/2

Therefore, y = 15°

For z:

2y + z = 180° { Being linear pair}

or, 30°+z = 180°

or, z = 180°-30°

or, z = 150°

Therefore, z = 150°.

Hope it helps...

6 0

3 years ago