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3 years ago

(Help) which of these is correct?

Chemistry

1 answer:

PolarNik [594]3 years ago

6 0

The third one I think

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Which of these pairs of elements have the same number of valence electrons

erastovalidia [21]

Beryllium (Be) and Calcium (Ca)

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3 years ago

W + BgCz2 --> WCz + Bg<br> Balance this equation

yanalaym [24]

Answer: W + BgCz2 arrow WCz + Bg

2 W + BgCz2 arrow 2 WCz + Bg

Explanation:

Cz has 2 so you balcne the other side of WCz.

Since you Balcanes the Cz you changed the W and you Balcanes the other W on the left side.

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3 years ago

How does a balanced chemical equation demonstrate conservation of mass?

Mariulka [41]

Answer:

A balanced chemical equation will demonstrate the law of conservation of mass because the amount of elements on one side (reactants) will equal the amount of elements on the other side (products).

Explanation:

CH₄ + 4Cl₂ -> CCl₄ + 4HCl

Reactants:

1 C

4 H

8 Cl

Products:

1 C

4 H

8 Cl

6 0

3 years ago

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Write a chemical equation for the dissolution of the AgCl precipitate upon the addition of NH,(aq).

Kobotan [32]

Explanation:

White precipitate of silver chloride get dissolves in excess ammonia to formation of complex between silver ions, chloride ions and ammonia molecules.

The chemical reaction is given as:

$AgCl(s)+2NH_3(aq)\rightarrow Ag[(NH_3)_2]^+Cl^-(aq)$

When 1 mole of silver chloride is added to 2 mole of an aqueous ammonia it form coordination complex of diaaminesilver(I) chloride.

7 0

3 years ago

Using the Rydberg formula, calculate the initial energy level when an electron in a hydrogen atom transitions into n= 2 and emit

EleoNora [17]

Answer:

Explanation:

Using the Rydberg formula as:

$\frac {1}{\lambda}=R_H\times Z^2\times (\frac {1}{n_{1}^2}-\frac {1}{n_{2}^2})$

where,

λ is wavelength of photon

R = Rydberg's constant (1.097 × 10⁷ m⁻¹)

Z = atomic number of atom

n₁ is the initial final level and n₂ is the final energy level

For Hydrogen atom, Z= 1

n₂ = 2

Wavelength = 410.1 nm

Also,

1 nm = 10⁻⁹ m

So,

Wavelength = 410.1 × 10⁻⁹ m

Applying in the formula as:

$\frac {1}{410.1\times 10^{-9}}=1.097\times 10^7\times 1^2\times (\frac {1}{n_{1}^2}-\frac {1}{2^2})$

Solving for n₁ , we get

n₁ ≅ 1

3 0

3 years ago

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