A 5.0 balloon containing nitrogen gas is cooled from 25 degrees to 5°C. What is the final volume of the balloon?
1 answer:
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Answer:
1) 1.202 L
, 2) 1.291 dg
, 3) 204.877 and 4) 1.04x
Explanation:
You need to review about conversion factors and how to use them in the correct order. You can cancel the units and get the ones that you need if you use the appropriate conversion factors, remember is a number that you can use to multiply or divide.
For your exercise:
1) The conversion factor is: 1 L = 1000 mL
You will need to divide by 1000 mL to obtain liters L
1202.57120 mL x = 1.202 L
2) The conversion factor is: 1 g = 10 dg
0.1290743 g x = 1.291 dg
For the next exercises, you need to follow some rules:
1. All numbers that are different from Zero (non-zero digits) are significant figures.
2.The Zeros between non-zeros digits (Imbedded zeros) always are significant, 2007.
3. If you want to be specific and want some zeros to be significant you need to add a decimal point. For example 500. or 500.0
4. Leading zeros (to the left) are not significant.
5. Trailing zeros (zeros to the right) in a whole number without decimal point are not significant.
3) 843.062 - 638.1848 = 204.8772
Now if we round to 6 significant figures we get 204.877
4)123.0 x 8.43 = 1036.89
Now we round to 3 significant figures because 8.43 has the least significant figures.
1.04x
Answer : The volume of the gas remaining is 56.5 liters.
The gas is hydrochloric acid and the formula of the gas is HCl.
The mass of produced is, 110.7 grams.
Explanation :
The balanced chemical reaction will be:
First we have to calculate the moles of and HCl
Molar mass of NH_3 = 17 g/mole
and,
Molar mass of HCl = 36.5 g/mole
Now we have to calculate the limiting and excess reagent.
From the balanced reaction we conclude that
As, 1 mole of HCl react with 1 mole of
So, 2.07 mole of HCl react with 2.07 mole of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and HCl is a limiting reagent and it limits the formation of product.
The remaining moles of HCl gas = 4.44 - 2.07 = 2.37 moles
Now we have to calculate the volume of the gas remaining.
Using ideal gas equation :
PV = nRT
where,
P = Pressure of gas = 752 mmHg = 0.989 atm (1 atm = 760 mmHg)
V = Volume of gas = ?
n = number of moles of gas = 2.37 moles
R = Gas constant = 0.0821 L.atm/mol.K
T = Temperature of gas =
Putting values in above equation, we get:
V = 56.5 L
Now we have to calculate the moles of
As, 1 mole of HCl react with 1 mole of
So, 2.07 mole of HCl react with 2.07 mole of
Now we have to calculate the mass of
Molar mass of = 53.5 g/mole
Thus, the volume of the gas remaining is 56.5 liters.
The gas is hydrochloric acid and the formula of the gas is HCl.
The mass of produced is, 110.7 grams.