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Ivanshal [37]
3 years ago
5

A 5.0 balloon containing nitrogen gas is cooled from 25 degrees to 5°C. What is the final volume of the balloon?

Chemistry
1 answer:
mylen [45]3 years ago
5 0

Answer:

5.4

Explanation:

V1=5.0

T1=25+ 273=298

V2= z(unknown)

T2=5+273=278

V1/T1 =V2/T2

V2=V1T2/T1

=5*298/278

=5.4

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Write a balenced chemical equation for the reaction: include abbreviation for the physical states-
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Answer:

2Na(s) + 2H2O(l) ------> 2NaOH(aq) + H2(g)

Explanation:

5 0
3 years ago
There are many factors that influence the population changes of an ecosystem. Which of these does not influence population size
devlian [24]

Answer:

B. An animal's weight

Explanation:

An animal's weight is the factor that does not influence population size in an ecosystem because this factor does not cause an increase or decrease the population of animals in an ecosystem. The birth and death rate of animals and number of animals in habitats are the factors that tells us about the increase and decrease in the population of organisms in an ecosystem but weight of organism can't affect the population.

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Static electricity is caused by ..
SpyIntel [72]

Answer:

ITS option B..

Explanation:

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7 0
2 years ago
2. The change in internal energy for the expansion of a gas sample is -4750 J. How much work is done if the gas sample loses 112
Radda [10]

Answer:

The work done by the gas expansion is 5875 J,

Since the work done is positive, the work is done by the gas on the surroundings.

Explanation:

Given;

change in internal energy, ΔU = -4750 J

heat transferred to the system, Q = 1125 J

The change in internal energy is given by;

ΔU = Q - W

Where;

W is the work done by the system

The work done by the system is calculated as;

W = Q - ΔU

W =  1125 - (-4750)

W = 1125 + 4750

W = 5875 J

Since the work done is positive, the work is done by the gas on the surroundings (energy flows from the gas to the surroundings).

Therefore, the work done by the gas expansion is 5875 J

7 0
3 years ago
Carbonic anhydrase of erythrocytes (Mr 30,000) has one of the highest turnover numbers known. It catalyzes the reversible hydrat
Afina-wow [57]

Explanation:

According to the given data, the turnover number can be calculated as follows.

      Turnover number = K_{cat} = \frac{V_{max}}{\text{Concentration of enzyme}}

     V_{max} = \frac{\text{Moles of CO_{2} hydrolyzed}{second}

Therefore, moles of CO_{2} hydrolyzed is as follows.

Moles of CO_{2} hydrolyzed = \frac{Mass of CO_{2}}{Molar mass of CO_{2}}

                 = \frac{0.30}{44}

                 = 0.00682 moles

Now, moles of CO_{2} hydolyzed per second is calculated as follows.

Moles of CO_{2} hydolyzed per second = \frac{0.00682}{60}

             = 1.137 \times 10^{-4} moles/second = V_{max}

And,

Moles of enzyme = \frac{Mass}{\text{Molar mass}}

                       = \frac{10.0 \mu g}{30000}

                       = 3.33 \times 10^{-10} moles

Therefore, the value of K_{cat} is as follows.

    K_{cat} = \frac{1.137 \times 10^{-4} moles}{3.333 \times 10^{-10} moles}

               = 0.3411 \times 10^{6} per second

               = 0.3411 \times 60 \times 10^{6} per minute

               = 20.466 \times 10^{6} per minute

Thus, we can conclude that the turnover number (K_{cat}) of carbonic anhydrase (in units of min^{-1}) is 20.466 \times 10^{6} per minute.

6 0
3 years ago
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