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salantis [7]
4 years ago
5

A cylindrical metal specimen 12.7 mm (0.5 in.)

Engineering
1 answer:
Liula [17]4 years ago
5 0

Answer:

Steel, Titanium and Tungsten

Explanation:

Given:-

- The diameter of the cylindrical specimen, d = 12.7 mm

- The length of the cylindrical specimen, L = 250 mm

- The tensile stress in the specimen, σ = 28 MPa

- Assume elastic deformation of the material up-to the specified tensile stress

Solution:-

- To determine or select suitable materials that are subjected to the given stress ( σ ) and an elongation constraint ( Δl ) or contraction of diameter ( Δd ). We need material intrinsic properties and relate them to our analysis.

- We studied two material intrinsic properties that is the Elastic Modulus ( E ) and Poisson ratio ( v ).

- Since, the question poses a constraint on the diameter. Note that the axis of stress applied ( axial ) and the contraction dimension are orthogonal to each other. In such case, we will determine the poisson ratio ( v ) of the suitable material as follows:

- We will first determine the permissible strain in the diametrical direction ( εx ). It is the ratio of allowable contraction of diameter ( Δd ) to the initial diameter ( d ):

                              εx = Δd / d

                              εx = ( -1.2*10^-3 )  / ( 12.7 )

                              εx = -0.00009

- The poisson ratio ( v ) of a material is defined as the negative ratio of the transversal strain ( εx ) to the axial strain ( εz ). The axial strain ( εz ) is determined as the ratio of elongation in length ( Δl ) to the initial length ( L ) of the specimen as follows:

                              εz = Δl / L

                              εz = ( 0.08 )  / ( 250 )

                              εz = 0.00032

- The poisson ratio ( v ) is expressed as:

                             v = - [ εx / εz ]

                              v = [ 0.00009 / 0.00032]

                              v = 0.2812

- Hooke's law gives us a linear relation between the applied stress ( σ ) and the engineering strain in the direction of applied stress. Since, the specimen is subjected to tensile stress and abides by the Hooke's law ( Elastic deformation ). The modulus of elasticity ( E ) is given as :

                              E = σ / εz

                              E = (28*10^6 ) / 0.00032

                              E = 87.5 GPa

- As per maximum elongation allowed the modulus of elasticity calculated above is the minimum value that must be satisfied by the selected material. We will use a list of materials ( ASTM ) standard and list a few that meet the elongation criteria as follows:

                  Copper, Nickel , Steel, Titanium , Tungsten

- From the above selected metals the most closely associated poisson ratio ( v ) calculated above would be:

                   Metals                         poisson ratio ( v ) range

                   Copper                                     0.33

                   Nickel                                       0.31

                   Steel                                    0.27–0.30

                   Titanium                              0.265–0.34

                   Tungsten                                  0.27

- The suitable materials would be:

                         Steel, Titanium and Tungsten

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