Answer:
Disaggregation
Explanation:
In a company it is a way to create operational plans that are focused, either by time or by section.
Based on the calculations, the magnitude (a) of it's total acceleration is equal to 2.71 m/s².
<u>Given the following data:</u>
- Angle of inclination = 10°.
- Radius of curvature, r = 40 meters.
- Acceleration of the minivan, A = 1.8 m/s².
- Initial velocity, u = 0 m/s (since it's starting from rest).
<h3>How to determine the magnitude (a) of it's total acceleration?</h3>
First of all, we would determine the final velocity of the minivan by applying the first equation of motion as follows:
V = u + at
V = 0 + 1.8 × 5
V = 9 m/s.
Next, we would calculate the centripetal acceleration of this minivan:
Ac = V²/r
Ac = 9²/40
Ac = 2.025 m/s².
Now, we can determine the magnitude (a) of it's total acceleration:
a = √(Ac² + A²)
a = √(2.025² + 1.8²)
a = 2.71 m/s².
Read more on acceleration here: brainly.com/question/24728358
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Answer:
(a) E = 0 N/C
(b) E = 0 N/C
(c) E = 7.78 x10^5 N/C
Explanation:
We are given a hollow sphere with following parameters:
Q = total charge on its surface = 23.6 μC = 23.6 x 10^-6 C
R = radius of sphere = 26.1 cm = 0.261 m
Permittivity of free space = ε0 = 8.85419 X 10−12 C²/Nm²
The formula for the electric field intensity is:
E = (1/4πεo)(Q/r²)
where, r = the distance from center of sphere where the intensity is to be found.
(a)
At the center of the sphere r = 0. Also, there is no charge inside the sphere to produce an electric field. Thus the electric field at center is zero.
<u>E = 0 N/C</u>
(b)
Since, the distance R/2 from center lies inside the sphere. Therefore, the intensity at that point will be zero, due to absence of charge inside the sphere (q = 0 C).
<u>E = 0 N/C</u>
(c)
Since, the distance of 52.2 cm is outside the circle. So, now we use the formula to calculate the Electric Field:
E = (1/4πεo)[(23.6 x 10^-6 C)/(0.522m)²]
<u>E = 7.78 x10^5 N/C</u>
Answer:
4mA
Explanation:
For this problem, we will simply apply Ohm's law:
V = IR
V/R = I
I = V / R
I = 12 volt / 3kΩ
I = 4mA
Hence, the current in the circuit is 4mA.
Cheers.
