1,05+ 0,69 + 1,82 = 3,56g of mixture
%CaCO₃: 1,82/3,56×100% = 0,5112×100% = 51,12%
x2=x+2 at x=−1 and x=2 so we have no need to worry about the end-points
f(x)=x+2−x^2
df/dx=1–2x
and that is zero (indicating a maximum) at x=1/2
So the maximum distance is f(1/2)=2.5–0.25=2.25
learn more about maximum distance between curves here:
brainly.com/question/1603866
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