The water outflow in 30 secs through 200 mm of the capillary tube is mathematically given as

<h3>What is the water outflow in 30 secs through 200 mm of the capillary tube?</h3>

Generally, the equation for Rate of flow of Liquid is mathematically given as

$$
Where dP is pressure difference r is the radius
is the viscosity of water
L is the length of the pipe


In $30s the quantity that flows out of the tube

In conclusion, the quantity that flows out of the tube

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Answer:
When electric voltage is applied, an electric field within the metal triggers the movement of the electrons, making them shift from one end to another end of the conductor. Electrons will move toward the positive side.
To solve this problem it is necessary to apply the concepts related to the Conservation of Energy, for which it is necessary that any decrease made through the potential energy, is equivalent to the gain given in the kinetic energy or vice versa.
Mathematically this can be expressed as

Since there is no final potential energy (the height is zero), and the initial potential energy is equivalent to the work done we have to






Therefore the non-conservative work was done on the boy is 1.4kJ
Using Newtons Second Law:
F = m×a
F = (0.25 kg)(-2 m/s²)
F = -0.5 N
<h2>The correct option is C</h2>
Answer:
The acceleration of the mosquito is 1 million (10⁶) times that of the car
Explanation:
From Newton’s Third Law, every action has an equal and opposite reaction. Therefore, when the car and the mosquito collide, the force the car exerts on the mosquito equals the force the mosquito exerts on the car.
F₁ = F₂
Also, from Newton’s Second Law, F₁ = ma₁
Force of the car, F₁ = 1000 * a₁
And force exerted by the mosquito, F₂ = 0.001 * a₂
Equating both sides
1000a₁ = 0.001a₂
Taking the ratio of the acceleration of the mosquito and that of the car, a₂/a₁:
a₂/a₁ = 1000/0.001
a₂/a₁ = 1000000
Therefore, the acceleration of the mosquito is 1000000 (10⁶) times that of the car