Work = Force * distance.
d = 8 m
W = 2400 J
F = ???
2400 = 8 * F
F = 2400/8
F = 300 N
The magnitude of the force required to stop the weight in 0.333 seconds is 67.6 N.
<h3>
Magnitude of required force to stop the weight</h3>
The magnitude of the force required to stop the weight in 0.333 seconds is calculated by applying Newton's second law of motion as shown below;
F = ma
F = m(v/t)
F = (mv)/t
F = (5 x 4.5)/0.333
F = 67.6 N
Thus, the magnitude of the force required to stop the weight in 0.333 seconds is 67.6 N.
Learn more about force here: brainly.com/question/12970081
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A hummingbird can flutter it's wings about 80 times per second.
4,800 divided by 60=80
Answer:
2.74
Explanation:
Magnification = image distance/object distance
Mag = v/u
Given
v = 46cm
u = 16.8
Magnification = 46/16.8
Magnification = 2.74
Hence the magnification is 2.74
<u>Answer:</u> The mass of the second car is 12666.7 kg
<u>Explanation:</u>
To calculate the mass of car, we use the equation of law of conservation of momentum, which is:
where,
= mass of car 1 = 9500 kg
= Initial velocity of car 1 = 14 m/s
= mass of car 2 = ? kg
= Initial velocity of car 2 = 0 m/s
= Final velocity = 6.0 m/s
Putting values in above equation, we get:
Hence, the mass of the second car is 12666.7 kg
