Answer:
the value of the final pressure is 0.168 atm
Explanation:
Given the data in the question;
Let p₁ be initial pressure, v₁ be initial volume.
After expansion, p₂ is final pressure and v₂ is final volume.
So using the following equations;
p₁v₁ = nRT
p₂v₂ = nRT
hence, p₁v₁ = p₂v₂
we find p₂
p₂ = p₁v₁ / v₂
given that; initial volume v₁ = 0.175 m³, Initial pressure p₁ = 0.350 atm,
final volume v₂ = 0.365 m³
we substitute
p₂ = ( 0.350 atm × 0.175 m³ ) / 0.365 m³
p₂ = 0.06125 atm-m³ / 0.365 m³
p₂ = 0.168 atm
Therefore, the value of the final pressure is 0.168 atm
Answer:
Sound wave is a longitudinal wave that propagates in a medium
Explanation:
<em>Part A:</em> (C) Sound wave is propagation of pressure fluctuations in a medium.
<em>Part B: </em>(C) Pressure fluctuations travel along the direction of propagation of the sound wave.
<em>Part C: </em>(A) Yes air play a role in the propagation of the human voice from one end of the lecture hall to the other.
Answer:
D
Explanation:
Because it is impossible for it to show the real depth of the ocean and how deep it is
Answer:
The answer to your question is Ke = 72 J
Explanation:
Kinetic energy depends on the speed of and object and its mass.
Data
mass = m = 4 kg
speed = v = 6 m/s
distance = d = 8 m
Kinetic energy = ke = ?
Formula
Ke = (1/2) mv²
Substitution
Ke = (1/2) (4)(6)²
Simplification
Ke = (1/2)(4)(36)
Ke = (1/2)(144)
Ke = 72 Joules
Result
Ke = 72 J
Answer:
second
Explanation:
the first let's everything appear red, the send would produce black(-ish) words on paper that's appealing blue
