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Andreas93 [3]
4 years ago
9

The infant's tendency to turn its head toward things that touch its cheek is known as the

Physics
2 answers:
jeka57 [31]4 years ago
8 0
The infants tendency to turn its head toward things that touch its cheek is known as the rooting reflex
katovenus [111]4 years ago
4 0

Answer:

I think it is <em><u>Rooting</u></em><em> </em><u><em>Reflex</em></u>

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A 70-kg astronaut (including spacesuit and equipment) is floating at rest a distance of 13 m from the spaceship when she runs ou
Keith_Richards [23]

Answer:

Explanation:

mass of the astronaut including the spacesuit, M=30

distance of astronaut from the spaceship, d = 13 m

mass of the oxygen tank, m = 3 kg

Speed of tank with respect to spaceship, v=15~m/s

a)

<u>Using the conservation of linear momentum:</u>

total momentum before collision = total momentum after collision

M.u=m.v+(M-m)v'

0=3\times 15+(70-15)\times v'

v'=0.82~m/s

b)

She mush hold her breath until she reaches the spaceship, i.e.

t=d/v'

t=13/0.82

t=15.89~s

4 0
3 years ago
A kid is on a stationary sled, on
gregori [183]

The mass of the kid and the sled is 50.0 kg

Explanation:

The sled starts to move when the force applied becomes larger than the maximum force of static friction, which is given by

F_{max} = \mu_s mg

where

\mu_s is the coefficient of static friction

m is the mass of the kid + the sled

g=9.8 m/s^2 is the acceleration of gravity

Here the sled starts moving when the force applied is 61.2 N, so

F_{max}=61.2 N

And we also know

\mu_s = 0.125

Therefore, we can find the mass of the kid and the sled by re-arranging the equation:

m=\frac{F_{max}}{\mu_s g}=\frac{61.2}{(0.125)(9.8)}=50.0 kg

Learn more about friction:

brainly.com/question/6217246

brainly.com/question/5884009

brainly.com/question/3017271

brainly.com/question/2235246

#LearnwithBrainly

6 0
4 years ago
Light of wavelength 648.0 nm is incident on a narrow slit. The diffraction pattern is viewed on a screen 57.5 cm from the slit.
boyakko [2]

Answer:

71.0 \mu m

Explanation:

The formula for the single-slit diffraction is

y=\frac{n\lambda D}{d}

where

y is the distance of the n-minimum from the centre of the diffraction pattern

D is the distance of the screen from the slit

d is the width of the slit

\lambda is the wavelength of the light

In this problem,

\lambda=648.0 nm=6.48\cdot 10^{-7}m

D=57.5 cm=0.575 m

y=1.05 cm=0.0105 m, with n=2 (this is the distance of the 2nd-order minimum from the central maximum)

Solving the formula for d, we find:

d=\frac{n\lambda D}{y}=\frac{2(6.48\cdot 10^{-7} m)(0.575 m)}{0.0105 m}=7.10\cdot 10^{-5} m= 71.0 \mu m

6 0
3 years ago
Why are there multiple versions of the scientific method?
gavmur [86]

Answer:

it's because some versions have more steps and others have less

4 0
3 years ago
A sound wave moving with a speed of 1500 m/s is sent from a submarine to the ocean floor. It reflects off the
Alekssandra [29.7K]

Answer:

the distance between the submarine and the ocean floor is 11,250 m

Explanation:

Given;

speed of the wave, v = 1500 m/s

time of motion of the wave, t = 15 s

The time taken to receive the echo is calculated as;

time \ of \ motion \ (t) = \frac{total \ distance }{speed \ of \ wave} = \frac{2d}{v}  \\\\2d = vt\\\\d = \frac{vt}{2} \\\\d = \frac{1500 \times 15}{2} \\\\d = 11,250 \ m

Therefore, the distance between the submarine and the ocean floor is 11,250 m

3 0
3 years ago
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