Ok, first we need to have in mind that to findthe distance we need to find also the time then we use the kinematic equations in the x-direction
<span>delta x = Vox*t + 1/2*a*t^2 </span> <span>since there is no horizontal acceleration, a = 0 m/s/s </span> <span>delta x = Vox*t </span> <span>40.0 m = 90 m/s * t </span> <span>t = 4/9 s </span>
<span>Now using this time you can calculate the vertical displacement due to gravity. </span> <span>delta y = Voy*t + 1/2*g*t^2 </span> <span>since there is no initial vertical velocity, Voy = 0m/s </span> <span>delta y = 1/2*g*t^2 </span> <span>delta y = 1/2*(-9.81 m/s/s)*(4/9 s)^2 </span> <span>solve for delta y and you will have the answer</span>
