Answer:
a) 2-chloro-2,3-dimethylbutane
b) 1-chloro-2,3-dimethylbutane
Explanation:
The <u>monochlorination</u> is a reaction in which we have to add <u>only 1 Cl</u> to the molecule. In this case, we will have to add a Cl to a <u>primary carbon</u> (a) and to a <u>tertiary carbon</u> (b).
In the monochlorination of the primary carbon, we can choose any <u>methyl carbon</u>. For the monochlorination of the terciary carbon we have to choose an <u>CH carbon</u>.
(See the figure)
Answer:
The molarity of urea in this solution is 6.39 M.
Explanation:
Molarity (M) is <em>the number of moles of solute in 1 L of solution</em>; that is

To calculate the molality, we need to know the number of moles of urea and the volume of solution in liters. We assume 100 grams of solution.
Our first step is to calculate the moles of urea in 100 grams of the solution,
using the molar mass a conversion factor. The total moles of 100g of a 37.2 percent by mass solution is
60.06 g/mol ÷ 37.2 g = 0.619 mol
Now we need to calculate the volume of 100 grams of solution, and we use density as a conversion factor.
1.032 g/mL ÷ 100 g = 96.9 mL
This solution contains 0.619 moles of urea in 96.9 mL of solution. To express it in molarity, we need to calculate the moles present in 1000 mL (1 L) of the solution.
0.619 mol/96.9 mL × 1000 mL= 6.39 M
Therefore, the molarity of the solution is 6.39 M.
Answer:
86.2% of Hg in the ore
Explanation:
Percent composition is defined as one hundred times the ratio between mass of an element in a compound and total mass of the compound. Formula is:
% composition = 
If an ore weights 681g and contains 587g of mercury, percent composition is:
(587g Hg / 681g) × 100 = <em>86.2% of Hg in the ore</em>
The fridge part can, just not the freezer, I think.