A reduced element (which gains electrons) and an oxidized element are required for redox reactions (gives electrons). It is not a redox reaction if we lack both of them (an element can not receive electrons if no element gives electrons and vice versa).
A reduced half and an oxidized half, which always occur together, make up redox processes. While the oxidized half experiences electron loss and an increase in oxidation number, the reduced half obtains electrons and the oxidation number declines. The mnemonic devices OIL RIG, which stand for "oxidation is loss" and "reduction is gain," are simple ways to memorize this. In a redox process, the total number of electrons stays constant. In the reduction half reaction, another species absorbs those that were released in the oxidation half reaction.
In a redox reaction, two species exchange electrons, and they are given unique names:
- The ion or molecule that accepts electrons is called the oxidizing agent - by accepting electrons it oxidizes other species.
- The ion or molecule that donates electrons is called the reducing agent - by giving electrons it reduces the other species.
Hence, what is oxidized is the reducing agent and what is reduced is the oxidizing agent.
<h3>
What is the purpose of oxidizing agents and reducing agents?</h3>
By reducing other compounds and shedding electrons, a reducing agent raises its oxidation state. An oxidizing agent gets electrons by oxidizing other compounds; as a result, its oxidation state lowers.
<h3>
What is a redox reaction?</h3>
Oxidation-reduction (or "redox") reactions are chemical processes in which electrons are exchanged between two substances. An oxidation-reduction reaction is any chemical process in which a molecule, atom, or ion alters the number of electrons it has, hence increasing or decreasing its oxidation state.
Learn more about redox reaction: brainly.com/question/13293425
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Answer:
The equilibrium constant of the given reaction is 0.01351.
Explanation:

The equilibrium constant of the reaction = 
...[1]

The equilibrium constant of the reaction = 
..[2]
![[Cl^-]=\frac{K_4\times [AgCl]}{[Ag^+]}](https://tex.z-dn.net/?f=%5BCl%5E-%5D%3D%5Cfrac%7BK_4%5Ctimes%20%5BAgCl%5D%7D%7B%5BAg%5E%2B%5D%7D)

The expression of equilibrium constant of the creation is ;
![K=\frac{[AgCl]^2[Pb^{2}]}{[PbCl_2]][Ag^+]^2}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BAgCl%5D%5E2%5BPb%5E%7B2%7D%5D%7D%7B%5BPbCl_2%5D%5D%5BAg%5E%2B%5D%5E2%7D)
Dividing [1] by [2]
![\frac{K_3}{K_4}=\frac{\frac{[Pb^{2+}][Cl^-]^2}{[PbCl_2]}}{\frac{[Ag^+][Cl^-]}{[AgCl]}}](https://tex.z-dn.net/?f=%5Cfrac%7BK_3%7D%7BK_4%7D%3D%5Cfrac%7B%5Cfrac%7B%5BPb%5E%7B2%2B%7D%5D%5BCl%5E-%5D%5E2%7D%7B%5BPbCl_2%5D%7D%7D%7B%5Cfrac%7B%5BAg%5E%2B%5D%5BCl%5E-%5D%7D%7B%5BAgCl%5D%7D%7D)
![\frac{K_3}{K_4}=\frac{[Pb^{2+}][Cl^-][AgCl]}{[PbCl_2][Ag^+]}](https://tex.z-dn.net/?f=%5Cfrac%7BK_3%7D%7BK_4%7D%3D%5Cfrac%7B%5BPb%5E%7B2%2B%7D%5D%5BCl%5E-%5D%5BAgCl%5D%7D%7B%5BPbCl_2%5D%5BAg%5E%2B%5D%7D)
Substituting the value of
from [2] :
![\frac{K_3}{K_4}=\frac{[Pb^{2+}][AgCl]}{[PbCl_2][Ag^+]}\times \frac{K_4\times [AgCl]}{[Ag^+]}](https://tex.z-dn.net/?f=%5Cfrac%7BK_3%7D%7BK_4%7D%3D%5Cfrac%7B%5BPb%5E%7B2%2B%7D%5D%5BAgCl%5D%7D%7B%5BPbCl_2%5D%5BAg%5E%2B%5D%7D%5Ctimes%20%5Cfrac%7BK_4%5Ctimes%20%5BAgCl%5D%7D%7B%5BAg%5E%2B%5D%7D)



The equilibrium constant of the given reaction is 0.01351.
Answer:
Explanation:
Exothermic Reactions
Exothermic Reactions
This means that the energy required to break the bonds in the reactants is less than the energy released when new bonds form in the products. Excess energy from the reaction is released as heat and light. Figure: Chemical reaction: A Hermite reaction, which produces molten iron.
Answer:
nice
Explanation:
you can do it just try your best
Answer:
(4) option is correct
Explanation:
Given that,
The conformation of 2-methyl-3-pentanol, as viewed along the C₂-C₃ bond.
We need to find the Newman structures
Using given structures
The structure of 2- methyl-3- pentanol is shown in figure.
Through C₂-C₃ carbon shown the structure of Newman projection in figure.
Here, carbon 2 is in front side and carbon 3 is in back side in the figure.
Hence, (4) option is correct.