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Scrat [10]
2 years ago
9

HELPPP ASAP PLSSS Which is the best estimate of the product of the fractions

Mathematics
1 answer:
yuradex [85]2 years ago
8 0
The best estimate is 1/2
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The fine schedule for overdue books at the county library is modeled by the values in the table.
Tasya [4]

Answer:

The answer would be B!

Step-by-step explanation:

In the chart if you divide the number of days over due to the cost of the fine, you get 5/2 every time. therefore, if y is the cost in cents and x is the days overdue, you would multiply x5/2 or y=5/2x, so your answer is B (y=5/2x).  

hoped this helped :D

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Please help me with this math problem
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The third one

Step-by-step explanation:

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When playing the roulette at a casino, you have exactly 1/35 chance of winning in each round if you play a single number. Your f
Vikentia [17]

Answer:

0.2275 = 22.75% probability that you actually won that round

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Fireworks going off

Event B: You won

Probability of fireworks going off.

100% of 1/35 = 0.0286(when you win)

10% of 34/35 = 0.9714(you lost). So

P(A) = 0.0286 + 0.1*0.9714 = 0.12574

Probability of you winning and fireworks going off:

100% of 1/35, so P(A \cap B) = 0.0286

If you failed to see the outcome of a round, but you see the fireworks going off, then what is the probability that you actually won that round?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0286}{0.12574} = 0.2275

0.2275 = 22.75% probability that you actually won that round

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3 years ago
What fraction is equivalent to 4/12
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fractions include 1/3,8/24,12/36 and so on

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Which equation has x=6 as the solution
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Answer:

Is there a picture? Or is it on a worksheet or something

Step-by-step explanation:

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