The trait perspective focuses primarily on describing
individual differences. The trait approach emphasizes the difference in traits
per individual. Traits are known to be constant or stable description of
individuals for a period of time. The trait approach sees the interaction of
traits among other personalities.
Answer:
Probability that the son will be:
color-blind = 1/2
blue eyed = 1/8
blue eyed and color-blind = 1/16
Explanation:
Mother : BbXcX
Father : BbXY
Colorblindness is X linked recessive trait hence will be caused when the son has XcY genotype.
XcX X XY :
Xc X
X XcX XX
Y XcY XY
Half of the sons will have normal vision and other half will be colorblind hence, there is 1/2 probability that the son will be colorblind.
Eye color is autosomal trait and blue color will be produced when the child has bb genotype.
Bb X Bb :
B b
B BB Bb
b Bb bb
1/4 of the children will have blue eyes. Since half of the children are expected to be males, 1/4 * 1/2 = 1/8 sons are expected to have blue eyes.
Probability of a son being blue eyed and color blind will be :
1/8 * 1/2 = 1/16
Answer:
A. 
B. 
C. 
D. 
Explanation:
Hello.
In this case, we must compute the final concentration in all the cases so we solve for it in the given equation:

Thus, we proceed as follows:
A. Here, the final diluted solution includes the 300 μL of the 5 mg/ml-BSA and the 700 μL of TBS.

B. Here, the final diluted solution includes the 50 μL of the 1.5 mg/ml-BSA, the 450 μL of water and the 500 μL of TBS.

C. Here, the final diluted solution includes the 10 μL of the 1 mg/ml-BSA and the 990 μL of TBS.

D. Here, the final diluted solution includes the 10 μL of the 0.1 mg/ml-BSA and the 990 μL of TBS.

Best regards.