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RUDIKE [14]
2 years ago
6

Near the equator, the sun heats the surface strongly, causing warm air to rise steadily. This creates the _________________, an

area of _________________pressure with very little wind.
Your answer:


horse lattitudes, high

horse latitudes, low

doldrums, high

doldrums, low
Chemistry
1 answer:
kenny6666 [7]2 years ago
8 0
Doldrums, low is the correct answer.
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What would happen to the pressure if the volume were reduced to 0.5 l and the temperature increased to 260 ∘c?
Vsevolod [243]
<span>The ideal gas law. PV=nRT pressure x volume = moles x Faraday's constant x Temp Kelvin (C+273) Original data Pressure 1 atmosphere Volume 1 liter Temp 25C = 298K New data Volume 0.5 liter pressure X Temp 260C = 533K P1v1T1 = P2v2T2 plug and chug. (1)(1)(293) = (x)(0.5)(533) Solve for X, which is the new pressure. </span>
8 0
3 years ago
True or false: a physical property is a characteristic of matter that you cannot observe or measure without changing the identit
Ganezh [65]
That is false, hope this helps.
4 0
3 years ago
How many grams of oxygen are produced when 7.65 moles of water is decomposed
maksim [4K]

Answer:

The answer to your question is 122.4 g of O₂

Explanation:

Data

mass of O₂ = ?

moles of H₂O = 7.65

Process

1.- Write the balanced chemical reaction

                   2H₂O  ⇒  2H₂  +  O₂

2.- Convert the moles of H₂O to grams

molar mass of H₂O = 2 + 16 = 18 g

                    18 g of H₂O ---------------- 1 mol

                      x                ----------------- 7.65 moles

                      x = (7.65 x 18) / 1

                      x = 137.7 g H₂O

3.- Calculate the grams of O₂

                 36 g of H₂O -------------------- 32 g of O₂

              137.7 g of H₂O -------------------  x

                        x = (32 x 137.7) / 36

                       x = 122.4 g of O₂

 

6 0
3 years ago
The immediate electron acceptor for the majority of the oxidative reactions of the citric acid cycle is.
Anna [14]

NAD serves as the bulk of the oxidative processes in the citric acid cycle's initial electron acceptor.

<h3>What are electron acceptors in citric acid cycle?</h3>
  • In the Krebs cycle, which transfers electrons via the electron transport chain with oxygen as the final acceptor, coenzymes like FAD and NAD+ are reduced.
  • In a single cycle, three NADH+ and one FADH2 are produced, and when the cycle enters the electron transport chain, 10 ATP is produced.
  • The final electron acceptor in the electron transport chain is oxygen. The proton gradient in the intermembrane gap is produced by NADH molecules donating electrons that are then transmitted through a number of different proteins.
<h3>What occurs throughout the citric acid cycle?</h3>

The cycle of citric acid: In the citric acid cycle, a six-carbon citrate molecule is created when an acetyl group from acetyl CoA is joined to a four-carbon oxaloacetate molecule.

Citrate is oxidized over a number of steps, generating two molecules of carbon dioxide for each acetyl group added to the cycle.

learn more about  citric acid cycle here

<u>brainly.com/question/14900762</u>

#SPJ4

6 0
2 years ago
As illustrated, the below manometer consists of a gas vessel and an open-ended U-tube containing a nonvolatile liquid with a den
STALIN [3.7K]

Answer:

1.01atm is the pressure of the gas

Explanation:

The difference in heights in the two sides is because of the difference in  pressure of the enclosed gas and the atmospheric pressure. This difference is in mm of the nonvolatile liquid. The difference in mm Hg is:

32.3mm * (0.993g/mL / 13.6g/mL) = 2.36mmHg

As atmospheric pressure is 765mm Hg and assuming the gas has more pressure than the atmospheric pressure (There is no illustration), the pressure of the gas is:

765mm Hg + 2.36mm Hg = 767.36 mmHg

In atm:

767.36 mmHg * (1atm / 760 mmHg) =

1.01atm is the pressure of the gas

5 0
3 years ago
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