You said "<span>A rocket's acceleration is 6.0 m/s2.".
That just means that its speed increases by 6 m/s every second.
Whenever you look at it, its speed is 6 m/s faster than it was
one second earlier.
If it starts out with zero speed, then its speed is 6 m/s after 1 second,
12 m/s after 2 seconds, 18 m/s after 3 seconds . . . etc.
How long does it take to reach 42 m/s ?
Well, how many times does it have to go 6 m/s FASTER
in order to build up to 42 m/s ?
That's just (42/6) = 7 times.
Writing it correctly, with the units and everything, it looks like this:
(42 m/s) / (6 m/s</span>²)
= (42/6) (m/s) / (m/s²)
= (42/6) (m/s · s²/m)
= 7 seconds
Answer:
Newtons first law states that:
<em>If</em><em> </em><em>a</em><em> </em><em>body</em><em> </em><em>i</em><em>s</em><em> </em><em>in</em><em> </em><em>rest</em><em> </em><em>or</em><em> </em><em>motion</em><em> </em><em>in</em><em> </em><em>a</em><em> </em><em>straight</em><em> </em><em>line</em><em>,</em><em> </em><em>it</em><em> </em><em>remains</em><em> </em><em>at</em><em> </em><em>rest</em><em> </em><em>or</em><em> </em><em>at</em><em> </em><em>motion</em><em> </em><em>in</em><em> </em><em>a</em><em> </em><em>straight</em><em> </em><em>line</em><em> </em><em>with</em><em> </em><em>constant</em><em> </em><em>speed</em><em> </em><em>until</em><em> </em><em>and</em><em> </em><em>unless</em><em> </em><em>and</em><em> </em><em>external</em><em> </em><em>unbalanced</em><em> </em><em>force</em><em> </em><em>acts</em><em> </em><em>on</em><em> </em><em>it</em><em>.</em>
<em>'</em><em>This</em><em> </em><em>law</em><em> </em><em>i</em><em>s</em><em> </em><em>also</em><em> </em><em>known</em><em> </em><em>as</em><em> </em><em>the</em><em> </em><em>law</em><em> </em><em>of</em><em> </em><em>Inertia</em><em>.</em><em>'</em>
Answer:

Explanation:
<u>Conservation of Momentum
</u>
The total momentum of a system of two particles is

Where m1,m2,v1, and v2 are the respective masses and velocities of the particles at a given time. Then, the two particles collide and change their velocities to v1' and v2'. The final momentum is now

The momentum is conserved if no external forces are acting on the system, thus

Let's put some numbers in the problem and say



120=120
It means that when the particles collide, the first mass returns at 6 m/s and the second continues in the same direction at 28 m/s