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Dvinal [7]
3 years ago
13

Find the domain of the graphed function.

Mathematics
2 answers:
Alika [10]3 years ago
8 0

Answer:

there is no ?

Step-by-step explanation:

Zinaida [17]3 years ago
4 0

Answer:

there is no graph

Step-by-step explanation:

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What is the slope of a line that contains the points (-6, 1)and (4 negative 4)​
Vesna [10]
-4/5 cause m=y^2-y^1/x^2-x^1
Btw check if it is correct
8 0
3 years ago
For the real-valued functions, find the composition and specify its domain using interval notation.
Helen [10]

Answer:

Composition:   f(x)\,^o\,h(x)=4\,\sqrt{x+4} -1

Domain = { x\,/\,x\geq \,-4  }

Step-by-step explanation:

Given

f(x)=4\,x-1\,\,\, and \,\,\, h(x)=\sqrt{x+4}

The requested composition becomes:

f(x)\,^o\,h(x)=f(h(x))\\f(x)\,^o\,h(x)=f(\sqrt{x+4} )\\f(x)\,^o\,h(x)=4\,\sqrt{x+4} -1

Then the Domain consists of all Real x-values for which the function is defined. In this case, the function is defined for all x-values for which the square root is defined, that is all x values for which:

x+4\geq \,0  (so the square root is defined in the Real number system)

This means x\geq \,-4

The Domain is then all the Real x-values such that x\geq \,-4

6 0
3 years ago
Consider the function f(x)=9-x^2/x^2-4 For which intervals is f(x) positive? Check ALL that apply.
solong [7]

Answer:

a. f (x) < 0 for x ∈ (-∞ ,-3)

b. f (x) > 0 for x ∈ (-3,-2)

c. f (x) < 0 for x ∈ (-2,2)

d. f (x) > 0 for x ∈ (2,3)

e.f (x) < 0 for x ∈ (3,∞)

Step-by-step explanation:

Here, the given function is:f(x)=   \frac{9-x^2}{x^2-4}

Now, to check for the sign of f(x) at x = k, put the value of x from the given interval.

We get:

<u>a. (-infinity, -3) </u>

put k = -4 from the given interval

We get f(-4)=   \frac{9-(-4)^2}{(-4)^2-4}  = \frac{9-16}{16-4}  = \frac{-7}{12}

⇒ f (x) < 0 for x ∈ (-∞ ,-3)

b. (-3, -2)

put k = -2.5 from the given interval

We get f(-2.5)=   \frac{9-(-2.5)^2}{(-2.5)^2-4}  = \frac{9-6.25}{6.25-4}  = \frac{2.75}{2.25}  > 0

⇒ f (x) > 0 for x ∈ (-3,-2)

c. (-2, 2)

put k = 0 from the given interval

We get f(0)=   \frac{9-(0)^2}{(0)^2-4}  = \frac{9}{-4}  = -\frac{9}{4}  < 0

⇒ f (x) < 0 for x ∈ (-2,2)

d. (2, 3)

put k =2.5 from the given interval

We get f(2.5)=   \frac{9-(2.5)^2}{(2.5)^2-4}  = \frac{9-6.25}{6.25-4}  = \frac{2.75}{2.25}  > 0

⇒ f (x) > 0 for x ∈ (2,3)

e. (infinity, 3)

put k = 4 from the given interval

We get f(4)=   \frac{9-(4)^2}{(4)^2-4}  = \frac{9-16}{16-4}  = \frac{-7}{12}

⇒ f (x) < 0 for x ∈ (3,∞)

7 0
4 years ago
Use the stem-and-leaf plot to answer the question.
Norma-Jean [14]

Answer:

75

Step-by-step explanation:

mode is the most occurring number

7 0
3 years ago
Read 2 more answers
Order from least to greatest 0,413, 0.056, 0.164, and 0.531
Alisiya [41]

Answer:0.056,0.164,0.413,0.531,

Step-by-step explanation:

4 0
3 years ago
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